b) Hence determine the number of sides of the polygon. Two lines have equations: L1: 3x – 4y + 12 = 0 and L2: 6x + 8y – 5 = Express each line in the form y = mx + c.

Here are the solutions to your questions: 5. b) Hence determine the number of sides of the polygon. Step 1: Identify the exterior angle. From part a) (solved previously), we found that x = 30. The exterior angle of the polygon is x^, so the exterior angle is 30^. Step 2: Calculate the number of sides. For any regular polygon, the sum of its exterior angles is 360^. The number of sides (n) is found by dividing 360^ by the measure of one exterior angle. n = (360^)/(Exterior Angle) n = (360^)/(30^) n = 12 The number of sides of the polygon is 12. Express each line in the form y = mx + c. For L1: 3x - 4y + 12 = 0 Step 1: Isolate the term containing y. Subtract 3x and 12 from both sides of the equation. -4y = -3x - 12 Step 2: Divide by the coefficient of y. Divide every term by -4. y = (-3x)/(-4) - (12)/(-4) y = (3)/(4)x + 3 The equation for L1 in the form y = mx + c is y = (3)/(4)x + 3. For L2: 6x + 8y - 5 = 0 Step 1: Isolate the term containing y. Subtract 6x and add 5 to both sides of the equation. 8y = -6x + 5 Step 2: Divide by the coefficient of y. Divide every term by 8. y = (-6x)/(8) + (5)/(8) y = -(3)/(4)x + (5)/(8) The equation for L2 in the form y = mx + c is y = -(3)/(4)x + (5)/(8). Last free one today — make it count tomorrow, or type /upgrade for unlimited.