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Benita invest £25000 into a fixed deposit account, which offers her an interest of rate of 12% time interest is compound annually, monthly, half yearly, quarterly for 4 years. Calculate the total amount accumulated in each.

Mathematics

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Step-by-step solution

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Here's how to calculate the total accumulated amount for Renita's investment under different compounding frequencies.

The formula for compound interest is:

A=P(1+rn)ntA = P \left(1 + \frac{r}{n}\right)^{nt}

Where:

  • AA = accumulated amount
  • PP = principal amount (£25,000)
  • rr = annual interest rate (12% or 0.12)
  • nn = number of times interest is compounded per year
  • tt = number of years (4 years)

1) Annually

  1. Identify the values for annual compounding.

    For annual compounding, n=1n=1.

    P=£25,000P = \pounds 25,000 r=0.12r = 0.12 n=1n = 1 t=4t = 4
  2. Substitute the values into the compound interest formula and calculate.

    A=25000(1+0.121)1×4A = 25000 \left(1 + \frac{0.12}{1}\right)^{1 \times 4} A=25000(1.12)4A = 25000 (1.12)^4 A=25000×1.57351936A = 25000 \times 1.57351936 A=£39337.98A = \pounds 39337.98

    The total amount accumulated annually is £39337.98\boxed{\text{£39337.98}}.

    2) Monthly

  3. Identify the values for monthly compounding.

    For monthly compounding, n=12n=12.

    P=£25,000P = \pounds 25,000 r=0.12r = 0.12 n=12n = 12 t=4t = 4
  4. Substitute the values into the compound interest formula and calculate.

    A=25000(1+0.1212)12×4A = 25000 \left(1 + \frac{0.12}{12}\right)^{12 \times 4} A=25000(1+0.01)48A = 25000 (1 + 0.01)^{48} A=25000(1.01)48A = 25000 (1.01)^{48} A=25000×1.61222607768A = 25000 \times 1.61222607768 A=£40305.65A = \pounds 40305.65

    The total amount accumulated monthly is £40305.65\boxed{\text{£40305.65}}.

    3) Half-yearly

  5. Identify the values for half-yearly compounding.

    For half-yearly compounding, n=2n=2.

    P=£25,000P = \pounds 25,000 r=0.12r = 0.12 n=2n = 2 t=4t = 4
  6. Substitute the values into the compound interest formula and calculate.

    A=25000(1+0.122)2×4A = 25000 \left(1 + \frac{0.12}{2}\right)^{2 \times 4} A=25000(1+0.06)8A = 25000 (1 + 0.06)^8 A=25000(1.06)8A = 25000 (1.06)^8 A=25000×1.5938480745A = 25000 \times 1.5938480745 A=£39846.20A = \pounds 39846.20

    The total amount accumulated half-yearly is £39846.20\boxed{\text{£39846.20}}.

    4) Quarterly

  7. Identify the values for quarterly compounding.

    For quarterly compounding, n=4n=4.

    P=£25,000P = \pounds 25,000 r=0.12r = 0.12 n=4n = 4 t=4t = 4
  8. Substitute the values into the compound interest formula and calculate.

    A=25000(1+0.124)4×4A = 25000 \left(1 + \frac{0.12}{4}\right)^{4 \times 4} A=25000(1+0.03)16A = 25000 (1 + 0.03)^{16} A=25000(1.03)16A = 25000 (1.03)^{16} A=25000×1.6047064441A = 25000 \times 1.6047064441 A=£40117.66A = \pounds 40117.66

    The total amount accumulated quarterly is £40117.66\boxed{\text{£40117.66}}.

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