Hannah invests R 6500 for 6 years. For the first 3 years, the interest rate is 12% per annum, compounded annually. She then withdraws R 4200. For the remaining 3 years, the interest rate is 8% per ann

The formula for compound interest is $A = P(1 + r)^t$.
Given:

• Principal ($P$) = R 6500
• Interest rate ($r$) = $12\%$ per annum $= 0.12$
• Time ($t$) = 3 years

$$A_1 = 6500(1 + 0.12)^3$$ $$A_1 = 6500(1.12)^3$$ $$A_1 = 6500 \times 1.404928$$ $$A_1 = 9132.032$$

Hannah withdraws R 4200.
New principal ($P_2$) = $A_1 - 4200$

$$P_2 = 9132.032 - 4200$$ $$P_2 = 4932.032$$

Given:

• New principal ($P_2$) = R 4932.032
• Interest rate ($r$) = $8\%$ per annum $= 0.08$
• Time ($t$) = 3 years

$$A_2 = 4932.032(1 + 0.08)^3$$ $$A_2 = 4932.032(1.08)^3$$ $$A_2 = 4932.032 \times 1.259712$$ $$A_2 = 6212.9409...$$

The amount in the account at the end of the six years is R 6212.94.

This matches option A.

The final answer is $\text{A. R 6212.94}$.