Bina situasi kehidupan harian berdasarkan ketaksamaan yang diberi. Create a daily life situation based on the given inequality.

Here's the solution for problem I.2:

• Problem I.2: "Jumlah sewa bulanan, RM$y$, sebuah kedai termasuk sewa kedai, iaitu RM3 750 dan bil utiliti yang lain." "The total monthly rent, RM$y$, of a shop includes the rent of the shop, which is RM3 750, and other utility bills."

  Step 1: Identify the components of the total monthly rent, $y$. The total monthly rent $y$ consists of a fixed shop rent of RM3 750 and additional utility bills. Step 2: Utility bills are typically non-negative, meaning they can be zero (e.g., no usage) or a positive amount. Therefore, the total monthly rent $y$ must be at least the fixed shop rent. Step 3: Formulate the inequality. Since $y$ includes RM3 750 plus an amount for utility bills (which is $\ge 0$), $y$ must be greater than or equal to RM3 750. $y \ge 3750$ The inequality is: $\boxed{y \ge 3750}$

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