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CLASS 10 MATHS - TOP 10 BOARD LEVEL MCQS HIGH DIFFICULTY

Mathematics

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1) If the zeroes of the polynomial x2−5x+6x^2 - 5x + 6 are α\alpha and β\beta, then α2+β2\alpha^2 + \beta^2 equals:

B) 13

  1. የፖሊኖሚሉን x2−5x+6x^2 - 5x + 6 ዜሮዎች α\alpha እና β\beta በመጠቀም የዜሮዎች ድምር እና ብዜት ማግኘት።

    ለአንድ ኳድራቲክ ፖሊኖሚል ax2+bx+c=0ax^2 + bx + c = 0፣ የዜሮዎች ድምር α+β=−ba\alpha + \beta = -\frac{b}{a} ሲሆን፣ የዜሮዎች ብዜት ደግሞ αβ=ca\alpha \beta = \frac{c}{a} ነው።
    እዚህ ላይ a=1a=1, b=−5b=-5, c=6c=6 ናቸው።
    ስለዚህ:

    α+β=−−51=5\alpha + \beta = -\frac{-5}{1} = 5 αβ=61=6\alpha \beta = \frac{6}{1} = 6
  2. α2+β2\alpha^2 + \beta^2ን ለማግኘት ቀመር መጠቀም።

    የሚከተለውን ማንነት እንጠቀማለን።

    (α+β)2=α2+β2+2αβ(\alpha + \beta)^2 = \alpha^2 + \beta^2 + 2\alpha\beta

    ይህን በማስተካከል α2+β2\alpha^2 + \beta^2ን እናገኛለን።

    α2+β2=(α+β)2−2αβ\alpha^2 + \beta^2 = (\alpha + \beta)^2 - 2\alpha\beta
  3. የተገኙትን ዋጋዎች ወደ ቀመሩ መተካት።

    α2+β2=(5)2−2(6)\alpha^2 + \beta^2 = (5)^2 - 2(6) α2+β2=25−12\alpha^2 + \beta^2 = 25 - 12 α2+β2=13\alpha^2 + \beta^2 = 13

    ስለዚህ ትክክለኛው መልስ B) 13 ነው።

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