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Classify 15 as odd or even and composite or prime. Find the reciprocal of the production rate (8 units/hr). Determine if sqrt(49) and sqrt(2) are rational or irrational. Find the reciprocal of 0.25. E

Mathematics

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1. Classification of 15
The number 15 is an odd number because it is not divisible by 2.
It is also a composite number because it has factors other than 1 and itself (its factors are 1, 3, 5, and 15).

2. Reciprocal of production rate

Step 1: Identify the production rate.
The production rate is 8 units per hour.

Step 2: Find the reciprocal.
The reciprocal of a number aa is 1a\frac{1}{a}.
The reciprocal of 8 is 18\frac{1}{8}.

18\boxed{\frac{1}{8}}

3. Rational or irrational numbers

a) 49\sqrt{49}

Step 1: Evaluate the square root.

49=7\sqrt{49} = 7

Step 2: Determine if it's rational or irrational.
Since 7 can be expressed as a fraction 71\frac{7}{1}, it is a rational number.

b) 2\sqrt{2}

Step 1: Evaluate the square root.

2≈1.41421356...\sqrt{2} \approx 1.41421356...

Step 2: Determine if it's rational or irrational.
Since 2\sqrt{2} cannot be expressed as a simple fraction of two integers and its decimal representation is non-terminating and non-repeating, it is an irrational number.

4. Reciprocal of 0.25

Step 1: Convert 0.25 to a fraction.

0.25=25100=140.25 = \frac{25}{100} = \frac{1}{4}

Step 2: Find the reciprocal of the fraction.
The reciprocal of 14\frac{1}{4} is 41=4\frac{4}{1} = 4.

4\boxed{4}

5. Express 53×545^3 \times 5^4 as a single power of 5

Step 1: Apply the law of indices am×an=am+na^m \times a^n = a^{m+n}.

53×54=53+45^3 \times 5^4 = 5^{3+4}

Step 2: Simplify the exponent.

53+4=575^{3+4} = 5^7 57\boxed{5^7}

6. Simplify 25×2324\frac{2^5 \times 2^3}{2^4}

Step 1: Simplify the numerator using am×an=am+na^m \times a^n = a^{m+n}.

25×23=25+3=282^5 \times 2^3 = 2^{5+3} = 2^8

Step 2: Substitute the simplified numerator back into the expression.

2824\frac{2^8}{2^4}

Step 3: Apply the law of indices aman=am−n\frac{a^m}{a^n} = a^{m-n}.

2824=28−4=24\frac{2^8}{2^4} = 2^{8-4} = 2^4 24\boxed{2^4}

7. Find log250 to 4 decimal places

Step 1: Use a calculator or logarithm tables to find the value of log⁡10(250)\log_{10}(250).

log⁡10(250)≈2.39794000867...\log_{10}(250) \approx 2.39794000867...

Step 2: Round the value to 4 decimal places.

2.39792.3979 2.3979\boxed{2.3979}

8. Simplify log100 + log0.1

Step 1: Evaluate each logarithm.

log⁡10(100)=log⁡10(102)=2\log_{10}(100) = \log_{10}(10^2) = 2 log⁡10(0.1)=log⁡10(10−1)=−1\log_{10}(0.1) = \log_{10}(10^{-1}) = -1

Step 2: Add the values.

2+(−1)=12 + (-1) = 1

Alternatively, using the logarithm law log⁡a+log⁡b=log⁡(ab)\log a + \log b = \log (ab):

log⁡10(100)+log⁡10(0.1)=log⁡10(100×0.1)\log_{10}(100) + \log_{10}(0.1) = \log_{10}(100 \times 0.1) log⁡10(10)=1\log_{10}(10) = 1 1\boxed{1}

9. Evaluate (27)23(27)^{\frac{2}{3}}

Step 1: Rewrite the expression using the property amn=(an)ma^{\frac{m}{n}} = (\sqrt[n]{a})^m.

(27)23=(273)2(27)^{\frac{2}{3}} = (\sqrt[3]{27})^2

Step 2: Calculate the cube root of 27.

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