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Classwork 1 whole = 3 thirds 1 whole = 6 sixths 1 half = 6 sixths 1 thirds = 6 sixths Copy and complete 1/3 = 2/6 2/3 = [ ] /6 1/2 = [ ] /6 1 = [ ] /6 4/6 = [ ] /3 2/6 = [ ] /3

Mathematics

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Here are the completed problems:

1) Classwork

  • a) 1 whole = 3\boxed{3} thirds
  • b) 1 whole = 6\boxed{6} sixths
  • c) 1 half = 3\boxed{3} sixths
  1. To convert 12\frac{1}{2} to sixths, we need to multiply the denominator 2 by 3 to get 6.

  2. We must also multiply the numerator 1 by 3.

    So, 1×3=31 \times 3 = 3. * Therefore, 12=36\frac{1}{2} = \frac{3}{6}.

    • d) 1 third = 2\boxed{2} sixths
  3. To convert 13\frac{1}{3} to sixths, we need to multiply the denominator 3 by 2 to get 6.

  4. We must also multiply the numerator 1 by 2.

    So, 1×2=21 \times 2 = 2. * Therefore, 13=26\frac{1}{3} = \frac{2}{6}.

    2) Copy and complete

    • a) 13=26\frac{1}{3} = \frac{2}{6} (Already completed)
    • b) 23=46\frac{2}{3} = \frac{\boxed{4}}{6}
  5. The denominator 3 was multiplied by 2 to get 6.

  6. Multiply the numerator 2 by 2 to find the missing value.

    2×2=42 \times 2 = 4.

    • c) 12=36\frac{1}{2} = \frac{\boxed{3}}{6}
  7. The denominator 2 was multiplied by 3 to get 6.

  8. Multiply the numerator 1 by 3 to find the missing value.

    1×3=31 \times 3 = 3.

    • d) 1=661 = \frac{\boxed{6}}{6}
  9. A whole number 1 can be written as a fraction where the numerator and denominator are the same.

  10. Since the denominator is 6, the numerator must also be 6.

    • e) 46=23\frac{4}{6} = \frac{\boxed{2}}{3}
  11. The denominator 6 was divided by 2 to get 3.

  12. Divide the numerator 4 by 2 to find the missing value.

    4÷2=24 \div 2 = 2.

    • f) 26=13\frac{2}{6} = \frac{\boxed{1}}{3}
  13. The denominator 6 was divided by 2 to get 3.

  14. Divide the numerator 2 by 2 to find the missing value.

    2÷2=12 \div 2 = 1.

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