Complete Table 3 for the equation y = x3 + 4x2 + x - 3. Use the scale of 2 cm to represent 1 unit on the x-axis and 2cm to represent 5 units on the y-axis. Draw the graph of y = x3 + 4x2 + x - 3. Use your graph to solve the equation x3 + 4x2 + 3/2x - 4 = 0.

Step 1: Complete Table 1 for $y = x^2 - 3x - 4$

For $x = -1$:
$y = (-1)^2 - 3(-1) - 4$
$y = 1 + 3 - 4$
$y = 0$

For $x = 0$:
$y = (0)^2 - 3(0) - 4$
$y = 0 - 0 - 4$
$y = -4$

For $x = 1$:
$y = (1)^2 - 3(1) - 4$
$y = 1 - 3 - 4$
$y = -6$

For $x = 2$:
$y = (2)^2 - 3(2) - 4$
$y = 4 - 6 - 4$
$y = -6$

For $x = 3$:
$y = (3)^2 - 3(3) - 4$
$y = 9 - 9 - 4$
$y = -4$

Completed table:

Step 2: Draw the graph
Use the scale: 1 cm represents 1 unit on the x-axis and 1 cm represents 1 unit on the y-axis.
Plot points: $(-1, 0)$, $(0, -4)$, $(1, -6)$, $(2, -6)$, $(3, -4)$.
Join with a smooth curve. The graph is a parabola opening upwards (vertex near $(1.5, -6.25)$).

Step 3: Use graph to solve $x^2 - 3x - 4 = 0$
The graph crosses y = 0 at $x = -1$ (exact) and at $x = 4$ (by extending the curve beyond x = 3).

Solutions: $\mathbf{x = -1,\ 4}$
x = -1,\ 4