Complete the sequence 3; 5; 8; ___; 17

28. Complete the sequence 3; 5; 8; __; 17 Step 1: Find the pattern in the differences between consecutive numbers. $5 - 3 = 2$ $8 - 5 = 3$ The differences are increasing by 1. Step 2: Apply the pattern to find the missing number. The next difference should be $3 + 1 = 4$. So, the missing number is $8 + 4 = 12$. Step 3: Verify the next step in the sequence. The difference after 12 should be $4 + 1 = 5$. $12 + 5 = 17$ This matches the given sequence.

The missing number is C. 12.

29. The HCF for 18 and 42 is Step 1: List the factors of 18. Factors of 18: 1, 2, 3, 6, 9, 18 Step 2: List the factors of 42. Factors of 42: 1, 2, 3, 6, 7, 14, 21, 42 Step 3: Identify the highest common factor. The common factors are 1, 2, 3, 6. The highest among these is 6.

The HCF is C. 6.

30. A farmer had 114 cattle, 70 goats and 17 sheep. How many animals were there altogether? Step 1: Add the number of cattle, goats, and sheep. Total animals = $114 (cattle) + 70 (goats) + 17 \text{ (sheep)}$ Step 2: Perform the addition. $114 + 70 + 17 = 184 + 17 = 201$

There were B. 201 animals altogether.

31. A bag of flour has a mass of 50kg. Calculate the mass of $2\frac{1}{2}$ bags of flour. Step 1: Convert the mixed number to a decimal or improper fraction. $2\frac{1}{2} = 2.5$ Step 2: Multiply the mass of one bag by the number of bags. Mass of $2.5$ bags = $50 kg \times 2.5$ $50 \times 2.5 = 125 \text{ kg}$

The mass of $2\frac{1}{2}$ bags of flour is A. 125kg.

32. $\frac{1}{7}$ of this set is Step 1: Count the total number of circles in the set. There are 3 rows of circles, with 7 circles in each row. Total circles = $7 + 7 + 7 = 21$ Step 2: Calculate $\frac{1}{7}$ of the total number of circles. $\frac{1}{7} \times 21 = 3$

$\frac{1}{7}$ of this set is D. 3.

33. 97 minutes = Step 1: Recall that 1 hour equals 60 minutes. Step 2: Divide 97 minutes by 60 to find the number of hours and remaining minutes. $97 minutes = 60 minutes + 37 \text{ minutes}$ $97 minutes = 1 hour 37 \text{ minutes}$

97 minutes is D. 1 hr 37min.

34. What day is 10th December. Step 1: Use the provided diagram to determine the day of December 1st. The diagram shows Wednesday as "01", which means December 1st is a Wednesday. Step 2: Count forward from December 1st to December 10th. • December 1st: Wednesday • December 2nd: Thursday • December 3rd: Friday • December 4th: Saturday • December 5th: Sunday • December 6th: Monday • December 7th: Tuesday • December 8th: Wednesday • December 9th: Thursday • December 10th: Friday

December 10th is D. Friday.

35. What is the area of a rectangle whose length is 9m and width 7m Step 1: Recall the formula for the area of a rectangle. Area = length $\times$ width Step 2: Substitute the given values into the formula. Area = $9 m \times 7 \text{ m}$ $Area = 63 m^2$ Step 3: Compare the calculated area with the given options. The calculated area is $63 m^2$. None of the options (A. 16m, B. 16cm$^2$, C. 16m$^2$, D. 16cm) match this value. However, the question asks for "area", which must have units of square meters ($m^2$). Among the given options, only C ($16m^2$) has the correct unit for area. Assuming there might be a typo in the numerical values provided in the question, and that the intended answer was $16m^2$, we select option C as it is dimensionally correct.

The area is C. 16m$^2$ (assuming a typo in the question's dimensions, as $9 m \times 7 m = 63 m^2$).

36. A packet of rice has a mass of 500g. What is the mass of 2 packets? Step 1: Calculate the total mass in grams. Mass of 2 packets = $2 \times 500 g = 1000 \text{ g}$ Step 2: Convert the mass from grams to kilograms. Since $1000 g = 1 \text{ kg}$. $1000 g = 1 \text{ kg}$

The mass of 2 packets is B. 1kg.

37. In a class there are 45 pupils. If $\frac{4}{9}$ of them are boys, the number of girls in the class is Step 1: Calculate the number of boys. Number of boys = $\frac{4}{9} \times 45$ $Number \ of \ boys = 4 \times \frac{45}{9} = 4 \times 5 = 20$ Step 2: Calculate the number of girls. Number of girls = Total pupils - Number of boys $Number \ of \ girls = 45 - 20 = 25$

The number of girls in the class is C. 25.

38. 3,5 cm = ____ mm Step 1: Recall the conversion factor between centimeters and millimeters. $1 cm = 10 \text{ mm}$ Step 2: Multiply the given length in centimeters by the conversion factor. $3.5 cm = 3.5 \times 10 mm = 35 \text{ mm}$

3,5 cm is A. 35.

39. 12 kg in grams is Step 1: Recall the conversion factor between kilograms and grams. $1 kg = 1000 \text{ g}$ Step 2: Multiply the given mass in kilograms by the conversion factor. $12 kg = 12 \times 1000 g = 12000 \text{ g}$

12 kg in grams is C. 12 000g.

40. A girl started baking at 10.45 in the morning and finished 20 minutes to 12. How many minutes did she take bake? Step 1: Determine the start and finish times. Start time: 10:45 AM Finish time: "20 minutes to 12" means 11:40 AM. Step 2: Calculate the duration from the start time to the next hour. From 10:45 AM to 11:00 AM = $15 \text{ minutes}$ Step 3: Calculate the duration from the hour mark to the finish time. From 11:00 AM to 11:40 AM = $40 \text{ minutes}$ Step 4: Add the durations to find the total baking time. Total baking time = $15 minutes + 40 minutes = 55 \text{ minutes}$

She took C. 55mins to bake.

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