Construct triangle ABC with side AB = 7cm, angle BAC = 50 degrees, and angle ABC = 70 degrees.

• Draw a straight line using a ruler.
• Stand your pencil or compass point at a starting point on the line and label it A.
• Using your ruler, measure $7 \text{ cm}$ from point A along the line. Stand your pencil or compass point at this $7 \text{ cm}$ mark and label it B.
• Draw a clear line segment connecting A and B.

• Place the center of your protractor exactly on point A.
• Align the baseline of the protractor with the line segment AB.
• Starting from $0^\circ$ on the scale that aligns with AB, count up to $50^\circ$.
• Make a small mark (this is your "specific arc" for the angle) on your paper at the $50^\circ$ reading.
• Draw a long ray (a line extending outwards) from point A passing through this mark.

• Place the center of your protractor exactly on point B.
• Align the baseline of the protractor with the line segment BA (make sure the $0^\circ$ mark is on the side of A).
• Starting from $0^\circ$ on the scale that aligns with BA, count up to $70^\circ$.
• Make a small mark (your "specific arc" for this angle) on your paper at the $70^\circ$ reading.
• Draw a long ray from point B passing through this mark.

• The point where the ray from A and the ray from B intersect is point C.
• You have now constructed triangle ABC.

Regarding part (c) from your image:
The question asks "What type of triangle is triangle ABC?".
Given $\angle BAC = 50^\circ$ and $\angle ABC = 70^\circ$, the third angle $\angle ACB$ would be:

Since all three angles ($50^\circ, 70^\circ, 60^\circ$) are less than $90^\circ$, triangle ABC is an acute-angled triangle, not a right-angled triangle.