Convert 300 litres of water into 500ml bottles. Also, calculate the time taken for a 1500m race with average speed of 5m/s.

From Question 1.1.1, the total water required is $300 \text{ litres}$.
We know that $1 \text{ L} = 1000 \text{ ml}$.

$$\text{Total water required in ml} = 300 \text{ L} \times 1000 \text{ ml/L} = 300000 \text{ ml}$$

$$\text{Number of bottles} = \frac{\text{Total water required in ml}}{\text{Capacity per bottle}}$$ $$\text{Number of bottles} = \frac{300000 \text{ ml}}{500 \text{ ml/bottle}} = 600 \text{ bottles}$$

The total number of bottles needed is $\boxed{\text{600 bottles}}$.

Question 1.1.6

The "total duration of the event" is not provided in the question or the preceding context. Therefore, this question cannot be answered without that information.

Question 1.1.7

The distance is $1500 \text{ m}$ and the average speed is $5 \text{ m/s}$.
We use the formula: $\text{Time} = \frac{\text{Distance}}{\text{Speed}}$.

$$\text{Time in seconds} = \frac{1500 \text{ m}}{5 \text{ m/s}} = 300 \text{ seconds}$$

We know that $1 \text{ minute} = 60 \text{ seconds}$.

$$\text{Minutes} = \frac{300 \text{ seconds}}{60 \text{ seconds/minute}} = 5 \text{ minutes}$$ $$\text{Remaining seconds} = 300 \text{ seconds} - (5 \text{ minutes} \times 60 \text{ seconds/minute}) = 300 - 300 = 0 \text{ seconds}$$

It takes $\boxed{\text{5 minutes and 0 seconds}}$ to complete the race.

Question 1.1.8

The dispensing rate is $0.25 \text{ litres per second}$.

$$\text{Time in seconds} = \frac{\text{Total water to dispense}}{\text{Dispensing rate}}$$ $$\text{Time in seconds} = \frac{50 \text{ litres}}{0.25 \text{ litres/second}} = 200 \text{ seconds}$$

We know that $1 \text{ minute} = 60 \text{ seconds}$.

$$\text{Time in minutes} = \frac{200 \text{ seconds}}{60 \text{ seconds/minute}} = \frac{10}{3} \text{ minutes}$$ $$\text{Time in minutes} \approx 3.33 \text{ minutes}$$

It will take $\boxed{\frac{10}{3} \text{ minutes}}$ or approximately $\boxed{\text{3.33 minutes}}$ to dispense 50 litres of water.