Convert 432,000sec=....days ....hours Find the next two numbers in the following sequence 3; 9; 27; 81; ....... Use the divisibility test method to check if 23,760 is divisible by 11. Solve 4x - 8 = 10x - 20

Here are the solutions to your questions: 4) Convert 432,000 sec = ... days ... hours Step 1: Convert seconds to hours. There are 3600 seconds in 1 hour (60 seconds/minute × 60 minutes/hour). Total hours = 432,000 sec3600 sec/hour = 120 hours Step 2: Convert total hours to days and remaining hours. There are 24 hours in 1 day. Number of days = 120 hours24 hours/day = 5 days Since 120 hours is exactly 5 days, there are no remaining hours. The conversion is 5 days 0 hours. --- 5) Find the next two numbers in the following sequence: 3; 9; 27; 81; ...... Step 1: Identify the pattern in the sequence. Observe the relationship between consecutive terms: 3 × 3 = 9 9 × 3 = 27 27 × 3 = 81 The sequence is a geometric progression where each term is multiplied by 3 to get the next term. Step 2: Calculate the next two numbers. The last given term is 81. Next number: 81 × 3 = 243 Second next number: 243 × 3 = 729 The next two numbers are 243, 729. --- 6) Use the divisibility test method to check if 23,760 is divisible by 11. Step 1: Apply the divisibility rule for 11. The rule states that a number is divisible by 11 if the alternating sum of its digits (starting from the rightmost digit) is 0 or a multiple of 11. For the number 23,760: 0 - 6 + 7 - 3 + 2 Step 2: Calculate the alternating sum. 0 - 6 + 7 - 3 + 2 = -6 + 7 - 3 + 2 = 1 - 3 + 2 = -2 + 2 = 0 Since the alternating sum is 0, the number 23,760 is divisible by 11. The number 23,760 is divisible by 11. --- 7) Solve 4x - 8 = 10x - 20 Step 1: Gather x terms on one side of the equation. Subtract 4x from both sides: 4x - 8 - 4x = 10x - 20 - 4x -8 = 6x - 20 Step 2: Gather constant terms on the other side of the equation. Add 20 to both sides: -8 + 20 = 6x - 20 + 20 12 = 6x Step 3: Solve for x. Divide both sides by 6: (12)/(6) = (6x)/(6) 2 = x The solution is x = 2. Drop the next question! 📸