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Find the coordinates of the point which divides the line segment joining the points P(11, 1) and Q(2, 7) internally in the ratio 2:1 and externally in the ratio 3:5.

Mathematics

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Answers

2 parts
i
(5, 5)
ii

(492,−8)\left(\frac{49}{2}, -8\right)

Step-by-step solution

4 steps

Here's how to solve question 6:

Given points are P(11,1)P(11, 1) and Q(2,7)Q(2, 7).
Let P=(x1,y1)=(11,1)P = (x_1, y_1) = (11, 1) and Q=(x2,y2)=(2,7)Q = (x_2, y_2) = (2, 7).

The section formula for a point (x,y)(x, y) that divides the line segment joining (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) in the ratio m:nm:n is:
For internal division:

(x,y)=(nx1+mx2m+n,ny1+my2m+n)(x, y) = \left( \frac{nx_1 + mx_2}{m+n}, \frac{ny_1 + my_2}{m+n} \right)

For external division:

(x,y)=(nx1−mx2n−m,ny1−my2n−m)(x, y) = \left( \frac{nx_1 - mx_2}{n-m}, \frac{ny_1 - my_2}{n-m} \right)

Part i· 2 steps

Internally in the ratio $2:1$

Here, m=2m=2 and n=1n=1.

  1. Apply the internal division formula for the x-coordinate.

    x=1⋅(11)+2⋅(2)2+1=11+43=153=5x = \frac{1 \cdot (11) + 2 \cdot (2)}{2+1} = \frac{11 + 4}{3} = \frac{15}{3} = 5
  2. Apply the internal division formula for the y-coordinate.

    y=1⋅(1)+2⋅(7)2+1=1+143=153=5y = \frac{1 \cdot (1) + 2 \cdot (7)}{2+1} = \frac{1 + 14}{3} = \frac{15}{3} = 5

    The coordinates of the point dividing PQ internally in the ratio 2:12:1 are (5,5)\boxed{(5, 5)}.

Part ii

(492,−8)\left(\frac{49}{2}, -8\right)

Externally in the ratio $3:5$

Here, m=3m=3 and n=5n=5.

  1. Apply the external division formula for the x-coordinate.

    x=5⋅(11)−3⋅(2)5−3=55−62=492x = \frac{5 \cdot (11) - 3 \cdot (2)}{5-3} = \frac{55 - 6}{2} = \frac{49}{2}
  2. Apply the external division formula for the y-coordinate.

    y=5⋅(1)−3⋅(7)5−3=5−212=−162=−8y = \frac{5 \cdot (1) - 3 \cdot (7)}{5-3} = \frac{5 - 21}{2} = \frac{-16}{2} = -8

    The coordinates of the point dividing PQ externally in the ratio 3:53:5 are (492,−8)\boxed{\left(\frac{49}{2}, -8\right)}.

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