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Copy and complete each of the following tables using the information provided: Minnie sells her AIDS ribbons for R8,50 each.

Mathematics

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Answer

To complete the table, we use the information that Minnie sells her AIDS ribbons for R8,50 each. This means the cost of ribbons is calculated by multiplying the number of ribbons by R8,50.

Step-by-step solution

4 steps

Assumption: The unit price of R8,50 per ribbon is used to calculate all missing values in the table.

  1. Determine the relationship between Cost and Number of ribbons.

    Given that each ribbon costs R8,50:
    Cost = Number of ribbons ×\times R8,50
    Number of ribbons = CostR8.50\frac{\text{Cost}}{\text{R}8.50}

  2. Calculate the missing "Number of ribbons" values.

    • For Cost = R8,50:
    Number of ribbons=R8.50R8.50=1\text{Number of ribbons} = \frac{\text{R}8.50}{\text{R}8.50} = 1
    • For Cost = R59,50:
    Number of ribbons=R59.50R8.50=7\text{Number of ribbons} = \frac{\text{R}59.50}{\text{R}8.50} = 7

  3. Calculate the missing "Cost" values.

    • For Number of ribbons = 20:
    Cost=20×R8.50=R170\text{Cost} = 20 \times \text{R}8.50 = \text{R}170
    • For Number of ribbons = 100:
    Cost=100×R8.50=R850\text{Cost} = 100 \times \text{R}8.50 = \text{R}850

  4. Complete the table with the calculated values.

    The completed table is:

    Cost (R)Number of ribbons8,50117459,507102101531317020850100\begin{array}{|c|c|} \hline \textbf{Cost (R)} & \textbf{Number of ribbons} \\ \hline 8,50 & \mathbf{1} \\ \hline 17 & 4 \\ \hline 59,50 & \mathbf{7} \\ \hline 102 & 10 \\ \hline 153 & 13 \\ \hline \mathbf{170} & 20 \\ \hline \mathbf{850} & 100 \\ \hline \end{array}
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