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Determine the correctness of statements regarding subtraction and solve the given problems.

Mathematics

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Here are the solutions to the problems:

1. Statement A: Large-number subtraction uses column method. Statement B: Borrowing is never needed in 4-digit subtraction.

  • Statement A is correct. Large-number subtraction is typically performed using the column method.
  • Statement B is incorrect. Borrowing (or regrouping) is often needed in 4-digit subtraction, just like in subtraction of smaller numbers, if a digit in the minuend is smaller than the corresponding digit in the subtrahend.

Therefore, only Statement A is correct.

The correct option is 1) Statement A is correct.

2. Match Column-I with Column-II.

  • A. Backward 10s: This refers to counting backward by tens.
    • Matches with 2. 90, 80, 70
  • B. Subtraction fact: This is a basic subtraction equation.
    • Matches with 1. 200−80=120200 - 80 = 120
  • C. Regrouping: This is another term for borrowing in subtraction.
    • Matches with 4. Borrowing
  • D. Profit: The formula for profit is Selling Price (SP) minus Cost Price (CP).
    • Matches with 3. SP - CP

So the correct matching order for A, B, C, D is 2, 1, 4, 3.

The correct option is 1) 2, 1, 4, 3.

3. 295×14295 \times 14 using expanded form is-

To multiply using the expanded form of 14, we write 14 as 10+410 + 4.
Then, we distribute the multiplication:

295×14=295×(10+4)295 \times 14 = 295 \times (10 + 4) 295×14=(295×10)+(295×4)295 \times 14 = (295 \times 10) + (295 \times 4)

The correct option is 1) (295×10)+(295×4)(295 \times 10) + (295 \times 4).

4. Match Column-I with Column-II.

  1. Calculate the products for each item in Column-I.

    • A. 65×2=13065 \times 2 = 130
    • B. 120×3=360120 \times 3 = 360
    • C. 295×10=2950295 \times 10 = 2950
    • D. 423×4=1692423 \times 4 = 1692
  2. Match the results with Column-II.

    • A. 130 matches with 2.
    • B. 360 matches with 1.
    • C. 2950 matches with 4.
    • D. 1692 matches with 3.

    So the correct matching order for A, B, C, D is 2, 1, 4, 3.

    The correct option is 3) 2, 1, 4, 3.

    5. A shelf holds 125 books. There are 14 shelves. How many books are there in total?

  3. Multiply the number of books per shelf by the number of shelves.

    Total books=Books per shelf×Number of shelves\text{Total books} = \text{Books per shelf} \times \text{Number of shelves} Total books=125×14\text{Total books} = 125 \times 14
  4. Perform the multiplication.

    125×14=125×(10+4)125 \times 14 = 125 \times (10 + 4) =(125×10)+(125×4)= (125 \times 10) + (125 \times 4) =1250+500= 1250 + 500 =1750= 1750

    There are a total of 1750 books.

    The correct option is 4) 1750.

    6. A man buys 45 packets of chocolates. Each packet contains 14 chocolates. He distributes 350 chocolates. How many does he have left?

  5. Calculate the total number of chocolates the man bought.

    Total chocolates bought=Number of packets×Chocolates per packet\text{Total chocolates bought} = \text{Number of packets} \times \text{Chocolates per packet} Total chocolates bought=45×14\text{Total chocolates bought} = 45 \times 14 45×14=630 chocolates45 \times 14 = 630 \text{ chocolates}
  6. Subtract the distributed chocolates from the total chocolates bought to find the remaining chocolates.

    Chocolates left=Total chocolates bought−Chocolates distributed\text{Chocolates left} = \text{Total chocolates bought} - \text{Chocolates distributed} Chocolates left=630−350\text{Chocolates left} = 630 - 350 Chocolates left=280 chocolates\text{Chocolates left} = 280 \text{ chocolates}

    The man has 280 chocolates left.

    The correct option is 4) 280.

    7. If 750 candles are packed in packets of 12, how many full packets and leftover candles?

  7. Divide the total number of candles by the number of candles per packet.

    Number of full packets=Total candlesCandles per packet\text{Number of full packets} = \frac{\text{Total candles}}{\text{Candles per packet}} Number of full packets=75012\text{Number of full packets} = \frac{750}{12}
  8. Perform the division to find the quotient and remainder.

    750÷12750 \div 12 750=12×62+6750 = 12 \times 62 + 6

    This means there are 62 full packets and 6 leftover candles.

    There are 62 packets, 6 left.

    The correct option is 1) 62 packets, 6 left.

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