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Decompose the rational expression (2x+1)/(x(x-1)) into partial fractions.

Mathematics

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Question 1:
We are given the equation:

2x+1x(x−1)=Ax+Bx−1\frac{2x+1}{x(x-1)} = \frac{A}{x} + \frac{B}{x-1}

To find the values of A and B, we combine the terms on the right side:

Ax+Bx−1=A(x−1)+Bxx(x−1)=Ax−A+Bxx(x−1)=(A+B)x−Ax(x−1)\frac{A}{x} + \frac{B}{x-1} = \frac{A(x-1) + Bx}{x(x-1)} = \frac{Ax - A + Bx}{x(x-1)} = \frac{(A+B)x - A}{x(x-1)}

Now, we compare the numerator of

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