Let the function be f(x)=secxcotx.
Step 1: Simplify the function using trigonometric identities.
We know that secx=cosx1 and cotx=sinxcosx.
f(x)=cosx1⋅sinxcosx
f(x)=sinx1
f(x)=cscx
Step 2: Find the derivative of the simplified function.
The derivative of cscx is −cscxcotx.
dxd(cscx)=−cscxcotx
Therefore, the derivative of secxcotx is:
−cscxcotx