Determining the values of y for the (x, y) on the Cartesian plane and join the points.

For $x = -2$: $y = 5(-2) + 6 = -10 + 6 = -4$
For $x = -1$: $y = 5(-1) + 6 = -5 + 6 = 1$
For $x = 0$: $y = 5(0) + 6 = 0 + 6 = 6$
For $x = 1$: $y = 5(1) + 6 = 5 + 6 = 11$
For $x = 2$: $y = 5(2) + 6 = 10 + 6 = 16$

The completed table is:

$$\begin{array}{|c|c|c|c|c|c|} \hline x & -2 & -1 & 0 & 1 & 2 \\ \hline y & \textbf{-4} & \textbf{1} & \textbf{6} & \textbf{11} & \textbf{16} \\ \hline \end{array}$$

For $x = -4$: $y = -4(-4) + 5 = 16 + 5 = 21$
For $x = -1$: $y = -4(-1) + 5 = 4 + 5 = 9$
For $x = 0$: $y = -4(0) + 5 = 0 + 5 = 5$
For $x = 1$: $y = -4(1) + 5 = -4 + 5 = 1$
For $x = 3$: $y = -4(3) + 5 = -12 + 5 = -7$

The completed table is:

$$\begin{array}{|c|c|c|c|c|c|} \hline x & -4 & -1 & 0 & 1 & 3 \\ \hline y & \textbf{21} & \textbf{9} & \textbf{5} & \textbf{1} & \textbf{-7} \\ \hline \end{array}$$

For $x = -2$: $y = -3(-2) - 2 = 6 - 2 = 4$
For $x = -1$: $y = -3(-1) - 2 = 3 - 2 = 1$
For $x = 0$: $y = -3(0) - 2 = 0 - 2 = -2$
For $x = 1$: $y = -3(1) - 2 = -3 - 2 = -5$
For $x = 2$: $y = -3(2) - 2 = -6 - 2 = -8$

The completed table is:

$$\begin{array}{|c|c|c|c|c|c|} \hline x & -2 & -1 & 0 & 1 & 2 \\ \hline y & \textbf{4} & \textbf{1} & \textbf{-2} & \textbf{-5} & \textbf{-8} \\ \hline \end{array}$$