Use the equations below to determine the values of y. Place points on the Cartesian plane and join the points.

For $x = -2$: $y = (-2)^2 + 4 = 4 + 4 = 8$
For $x = -1$: $y = (-1)^2 + 4 = 1 + 4 = 5$
For $x = 0$: $y = (0)^2 + 4 = 0 + 4 = 4$
For $x = 1$: $y = (1)^2 + 4 = 1 + 4 = 5$
For $x = 2$: $y = (2)^2 + 4 = 4 + 4 = 8$

The completed table is:

$$\begin{array}{|c|c|c|c|c|c|} \hline x & -2 & -1 & 0 & 1 & 2 \\ \hline y & \textbf{8} & \textbf{5} & \textbf{4} & \textbf{5} & \textbf{8} \\ \hline \end{array}$$

(Assuming the $x$ values follow the pattern -2, -1, 0, 1, 2 based on the previous questions.)
For $x = -2$: $y = (-2)^2 + 5 = 4 + 5 = 9$
For $x = -1$: $y = (-1)^2 + 5 = 1 + 5 = 6$
For $x = 0$: $y = (0)^2 + 5 = 0 + 5 = 5$
For $x = 1$: $y = (1)^2 + 5 = 1 + 5 = 6$
For $x = 2$: $y = (2)^2 + 5 = 4 + 5 = 9$

The completed table is:

$$\begin{array}{|c|c|c|c|c|c|} \hline x & -2 & -1 & 0 & 1 & 2 \\ \hline y & \textbf{9} & \textbf{6} & \textbf{5} & \textbf{6} & \textbf{9} \\ \hline \end{array}$$