How to find median and mode and range in the table

Mathematics

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Answer

30 - 39
49

Okay, let's find the median, mode, and range using the grouped frequency table.

Here is our grouped frequency table:

Score IntervalFrequency10−19320−29330−39540−49350−592Total16\begin{array}{|c|c|} \hline \textbf{Score Interval} & \textbf{Frequency} \\ \hline 10 - 19 & 3 \\ 20 - 29 & 3 \\ 30 - 39 & 5 \\ 40 - 49 & 3 \\ 50 - 59 & 2 \\ \hline \textbf{Total} & \textbf{16} \\ \hline \end{array}

1. How to find the Mode from a grouped frequency table:
For grouped data, we find the modal class. This is the class interval with the highest frequency.

  • Look at the "Frequency" column. The highest frequency is 5.
  • The class interval corresponding to this frequency is 30 - 39. So, the modal class is 30−39\boxed{30 - 39}. This means the most common scores fall within this range.

2. How to find the Median from a grouped frequency table:
For grouped data, we find the median class. This is the class interval where the middle value lies.

  • First, find the position of the median. Since there are 16 total scores (N=16), the median is between the N2\frac{N}{2}-th and (N2+1)(\frac{N}{2} + 1)-th values, which are the 8th and 9th values.
  • Now, we find which class interval contains these values by adding up frequencies (cumulative frequency):
    • 10 - 19: 3 scores (scores 1, 2, 3)
    • 20 - 29: 3 scores. Cumulative: 3+3=63 + 3 = 6 scores (scores 4, 5, 6)
    • 30 - 39: 5 scores. Cumulative: 6+5=116 + 5 = 11 scores (scores 7, 8, 9, 10, 11)
  • Since the 8th and 9th scores fall within the 30 - 39 interval, this is the median class. So, the median class is 30−39\boxed{30 - 39}.

3. How to find the Range from a grouped frequency table:
The range is the difference between the upper limit of the highest class and the lower limit of the lowest class.

  • Highest class interval: 50 - 59. Its upper limit is 59.
  • Lowest class interval: 10 - 19. Its lower limit is 10.
Range=Upper limit of highest class−Lower limit of lowest class=59−10=49\text{Range} = \text{Upper limit of highest class} - \text{Lower limit of lowest class} = 59 - 10 = 49

The range is 49\boxed{49}.

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