Differentiate between Differentiation and Integration. Determine the slope of A(-2, -4) and B(-3, -2). If y = 2x2 + 5 for 0 <= x <= 3.0, find y when x = 0.5. If y = ax^n, dy/dx = __. If y = x2, dy/dx
|Mathematics
Differentiate between Differentiation and Integration. Determine the slope of A(-2, -4) and B(-3, -2). If y = 2x2 + 5 for 0 <= x <= 3.0, find y when x = 0.5. If y = ax^n, dy/dx = __. If y = x2, dy/dx
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Welcome back Mary — missed you this week.
Here are the solutions to your questions:
1. Differentiate between Differentiation and Integration.
Differentiation is the process of finding the rate of change of a function, which gives the slope of the tangent line to the function's graph at any point. Integration is the process of finding the area under a curve, which is essentially the reverse operation of differentiation.
2. Determine the slope of A(-2, -4) and B(-3, -2).
Step 1: Use the slope formula m=x2−x1y2−y1.
Given points A(x1,y1)=(−2,−4) and B(x2,y2)=(−3,−2).
Step 2: Substitute the coordinates into the formula.
m=−3−(−2)−2−(−4)m=−3+2−2+4m=−12m=−2
The slope is −2.
3. If y=2x2+5 for 0≤x≤3.0, find y when x=0.5.
Step 1: Substitute x=0.5 into the equation.
y=2(0.5)2+5
Step 2: Calculate the value of y.
y=2(0.25)+5y=0.5+5y=5.5
The value of y is 5.5.
4. If y=axn, dxdy=_____
Using the power rule for differentiation, dxd(cxn)=cnxn−1.
dxdy=anxn−1
5. If y=x2, dxdy=_____
Using the power rule, dxd(xn)=nxn−1.
dxdy=2x2−1dxdy=2x
6. If y=2x5, dxdy=_____
Using the power rule, dxd(cxn)=cnxn−1.
dxdy=2⋅5x5−1dxdy=10x4
7. A polynomial is _____
This question is incomplete. A polynomial is an expression consisting of variables and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables.
8. If y=5x3+4x2−3x+9, dxdy=_____
Step 1: Differentiate each term using the power rule.
dxdy=dxd(5x3)+dxd(4x2)−dxd(3x)+dxd(9)
Step 2: Apply the power rule to each term.
dxdy=5(3)x3−1+4(2)x2−1−3(1)x1−1+0dxdy=15x2+8x−3
The derivative is 15x2+8x−3.
9. Find the absolute value of dxdy for y=3x4−7x3+4x2−3x−4 at x=2.
Step 1: Find the first derivative dxdy.
dxdy=dxd(3x4−7x3+4x2−3x−4)dxdy=3(4)x3−7(3)x2+4(2)x1−3(1)x0−0dxdy=12x3−21x2+8x−3
Step 2: Substitute x=2 into the derivative.
dxdyx=2=12(2)3−21(2)2+8(2)−3dxdyx=2=12(8)−21(4)+16−3dxdyx=2=96−84+16−3dxdyx=2=12+16−3dxdyx=2=28−3dxdyx=2=25
Step 3: Find the absolute value.
∣dxdyx=2∣=∣25∣=25
The absolute value of the derivative at x=2 is 25.
10. Find dx2d2y for y=3x4−7x3+4x2−3x−4 at x=2.
Step 1: From Question 9, the first derivative is dxdy=12x3−21x2+8x−3.
Step 2: Find the second derivative dx2d2y by differentiating dxdy.
dx2d2y=dxd(12x3−21x2+8x−3)dx2d2y=12(3)x2−21(2)x1+8(1)x0−0dx2d2y=36x2−42x+8
Step 3: Substitute x=2 into the second derivative.
dx2d2yx=2=36(2)2−42(2)+8dx2d2yx=2=36(4)−84+8dx2d2yx=2=144−84+8dx2d2yx=2=60+8dx2d2yx=2=68
The second derivative at x=2 is 68.
11. What is the value of dx2d2y if y=3x4−7x3+4x2−3x−4 at x=−2.
Step 1: From Question 10, the second derivative is dx2d2y=36x2−42x+8.
Step 2: Substitute x=−2 into the second derivative.
dx2d2yx=−2=36(−2)2−42(−2)+8dx2d2yx=−2=36(4)+84+8dx2d2yx=−2=144+84+8dx2d2yx=−2=228+8dx2d2yx=−2=236
The value of the second derivative at x=−2 is 236.
12. If y=sinx, dxdy=_____
The derivative of sinx is cosx.
dxdy=cosx
13. If y=cosx, dxdy=_____
The derivative of cosx is −sinx.
dxdy=−sinx
14. What is a Curve?
A curve is a continuous and smooth line that is not necessarily straight. In mathematics, it often represents the graph of a function or a set of points satisfying a certain equation.
15. If y=cosxsinx, dxdy=_____
Step 1: Recognize that y=cosxsinx=tanx.
Step 2: Differentiate y=tanx.
dxdy=dxd(tanx)dxdy=sec2x
Alternatively, using the quotient rule:
Let u=sinx and v=cosx. Then dxdu=cosx and dxdv=−sinx.
The quotient rule is dxd(vu)=v2vdxdu−udxdv.
dxdy=(cosx)2cosx(cosx)−sinx(−sinx)dxdy=cos2xcos2x+sin2x
Using the identity sin2x+cos2x=1:
dxdy=cos2x1dxdy=sec2x
The derivative is sec2x.
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Welcome back Mary — missed you this week. Here are the solutions to your questions: 1.
Differentiate between Differentiation and Integration. Determine the slope of A(-2, -4) and B(-3, -2). If y = 2x2 + 5 for 0 <= x <= 3.0, find y when x = 0.5. If y = ax^n, dy/dx = __. If y = x2, dy/dx
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
Welcome back Mary — missed you this week. Here are the solutions to your questions: 1. Differentiate between Differentiation and Integration. Differentiation is the process of finding the rate of change of a function, which gives the slope of the tangent line to the function's graph at any point. Integration is the process of finding the area under a curve, which is essentially the reverse operation of differentiation. 2. Determine the slope of A(-2, -4) and B(-3, -2). Step 1: Use the slope formula m = (y_2 - y_1)/(x_2 - x_1). Given points A(x_1, y_1) = (-2, -4) and B(x_2, y_2) = (-3, -2). Step 2: Substitute the coordinates into the formula. m = (-2 - (-4))/(-3 - (-2)) m = (-2 + 4)/(-3 + 2) m = (2)/(-1) m = -2 The slope is -2. 3. If y = 2x^2 + 5 for 0 x 3.0, find y when x = 0.5. Step 1: Substitute x = 0.5 into the equation. y = 2(0.5)^2 + 5 Step 2: Calculate the value of y. y = 2(0.25) + 5 y = 0.5 + 5 y = 5.5 The value of y is 5.5. 4. If y = ax^n, (dy)/(dx) = \_\_\_\_\_ Using the power rule for differentiation, (d)/(dx)(cx^n) = cnx^n-1. (dy)/(dx) = anx^n-1 5. If y = x^2, (dy)/(dx) = \_\_\_\_\_ Using the power rule, (d)/(dx)(x^n) = nx^n-1. (dy)/(dx) = 2x^2-1 (dy)/(dx) = 2x 6. If y = 2x^5, (dy)/(dx) = \_\_\_\_\_ Using the power rule, (d)/(dx)(cx^n) = cnx^n-1. (dy)/(dx) = 2 · 5x^5-1 (dy)/(dx) = 10x^4 7. A polynomial is \_\_\_\_\_ This question is incomplete. A polynomial is an expression consisting of variables and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables. 8. If y = 5x^3 + 4x^2 - 3x + 9, (dy)/(dx) = \_\_\_\_\_ Step 1: Differentiate each term using the power rule. (dy)/(dx) = (d)/(dx)(5x^3) + (d)/(dx)(4x^2) - (d)/(dx)(3x) + (d)/(dx)(9) Step 2: Apply the power rule to each term. (dy)/(dx) = 5(3)x^3-1 + 4(2)x^2-1 - 3(1)x^1-1 + 0 (dy)/(dx) = 15x^2 + 8x - 3 The derivative is 15x^2 + 8x - 3. 9. Find the absolute value of (dy)/(dx) for y = 3x^4 - 7x^3 + 4x^2 - 3x - 4 at x = 2. Step 1: Find the first derivative (dy)/(dx). (dy)/(dx) = (d)/(dx)(3x^4 - 7x^3 + 4x^2 - 3x - 4) (dy)/(dx) = 3(4)x^3 - 7(3)x^2 + 4(2)x^1 - 3(1)x^0 - 0 (dy)/(dx) = 12x^3 - 21x^2 + 8x - 3 Step 2: Substitute x = 2 into the derivative. (dy)/(dx)|_x=2 = 12(2)^3 - 21(2)^2 + 8(2) - 3 (dy)/(dx)|_x=2 = 12(8) - 21(4) + 16 - 3 (dy)/(dx)|_x=2 = 96 - 84 + 16 - 3 (dy)/(dx)|_x=2 = 12 + 16 - 3 (dy)/(dx)|_x=2 = 28 - 3 (dy)/(dx)|_x=2 = 25 Step 3: Find the absolute value. |(dy)/(dx)|_x=2| = |25| = 25 The absolute value of the derivative at x=2 is 25. 10. Find (d^2y)/(dx^2) for y = 3x^4 - 7x^3 + 4x^2 - 3x - 4 at x = 2. Step 1: From Question 9, the first derivative is (dy)/(dx) = 12x^3 - 21x^2 + 8x - 3. Step 2: Find the second derivative (d^2y)/(dx^2) by differentiating (dy)/(dx). (d^2y)/(dx^2) = (d)/(dx)(12x^3 - 21x^2 + 8x - 3) (d^2y)/(dx^2) = 12(3)x^2 - 21(2)x^1 + 8(1)x^0 - 0 (d^2y)/(dx^2) = 36x^2 - 42x + 8 Step 3: Substitute x = 2 into the second derivative. (d^2y)/(dx^2)|_x=2 = 36(2)^2 - 42(2) + 8 (d^2y)/(dx^2)|_x=2 = 36(4) - 84 + 8 (d^2y)/(dx^2)|_x=2 = 144 - 84 + 8 (d^2y)/(dx^2)|_x=2 = 60 + 8 (d^2y)/(dx^2)|_x=2 = 68 The second derivative at x=2 is 68. 11. What is the value of (d^2y)/(dx^2) if y = 3x^4 - 7x^3 + 4x^2 - 3x - 4 at x = -2. Step 1: From Question 10, the second derivative is (d^2y)/(dx^2) = 36x^2 - 42x + 8. Step 2: Substitute x = -2 into the second derivative. (d^2y)/(dx^2)|_x=-2 = 36(-2)^2 - 42(-2) + 8 (d^2y)/(dx^2)|_x=-2 = 36(4) + 84 + 8 (d^2y)/(dx^2)|_x=-2 = 144 + 84 + 8 (d^2y)/(dx^2)|_x=-2 = 228 + 8 (d^2y)/(dx^2)|_x=-2 = 236 The value of the second derivative at x=-2 is 236. 12. If y = x, (dy)/(dx) = \_\_\_\_\_ The derivative of x is x. (dy)/(dx) = x 13. If y = x, (dy)/(dx) = \_\_\_\_\_ The derivative of x is - x. (dy)/(dx) = - x 14. What is a Curve? A curve is a continuous and smooth line that is not necessarily straight. In mathematics, it often represents the graph of a function or a set of points satisfying a certain equation. 15. If y = ( x)/( x), (dy)/(dx) = \_\_\_\_\_ Step 1: Recognize that y = ( x)/( x) = x. Step 2: Differentiate y = x. (dy)/(dx) = (d)/(dx)( x) (dy)/(dx) = ^2 x Alternatively, using the quotient rule: Let u = x and v = x. Then (du)/(dx) = x and (dv)/(dx) = - x. The quotient rule is (d)/(dx)((u)/(v)) = (vdu)/(dx) - u(dv)/(dx)v^2. (dy)/(dx) = ( x ( x) - x (- x))/(( x)^2) (dy)/(dx) = (^2 x + ^2 x)/(^2 x) Using the identity ^2 x + ^2 x = 1: (dy)/(dx) = (1)/(^2 x) (dy)/(dx) = ^2 x The derivative is ^2 x. Send me the next one 📸