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Differentiate with respect to x: ((1+x2))/(x2)

Mathematics

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Question 3

a) Differentiate with respect to x: ln⁡(1+x2)x2\frac{\ln(1+x^2)}{x^2}

Step 1: Identify the function as a quotient and define uu and vv.
Let f(x)=uvf(x) = \frac{u}{v}, where u=ln⁡(1+x2)u = \ln(1+x^2) and v=x2v = x^2.

Step 2: Find the derivatives of uu and vv.
Using the chain rule for uu:

dudx=11+x2⋅ddx(1+x2)=2x1+x2\frac{du}{dx} = \frac{1}{1+x^2} \cdot \frac{d}{dx}(1+x^2) = \frac{2x}{1+x^2}

Using the power rule for vv:

dvdx=2x\frac{dv}{dx} = 2x

Step 3: Apply the quotient rule, ddx(uv)=vdudx−udvdxv2\frac{d}{dx}\left(\frac{u}{v}\right) = \frac{v\frac{du}{dx} - u\frac{dv}{dx}}{v^2}.

f′(x)=x2(2x1+x2)−ln⁡(1+x2)(2x)(x2)2f'(x) = \frac{x^2\left(\frac{2x}{1+x^2}\right) - \ln(1+x^2)(2x)}{(x^2)^2} f′(x)=2x31+x2−2xln⁡(1+x2)x4f'(x) = \frac{\frac{2x^3}{1+x^2} - 2x\ln(1+x^2)}{x^4}

Step 4: Simplify the expression.
Factor out 2x2x from the numerator:

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