Directions: Find the area of the following figures. 3.

The figure is a trapezoid. The parallel bases are the top and bottom sides.
Base 1 ($b_1$) = $13 \text{ m}$
Base 2 ($b_2$) = $12 \text{ cm}$
The right angle symbol indicates that the side labeled $15 \text{ cm}$ is perpendicular to the $12 \text{ cm}$ base. Therefore, the height ($h$) = $15 \text{ cm}$.

To perform calculations, all units must be consistent. Convert $b_1$ from meters to centimeters:
$b_1 = 13 \text{ m} \times 100 \text{ cm/m} = 1300 \text{ cm}$.

Now we have:
$b_1 = 1300 \text{ cm}$
$b_2 = 12 \text{ cm}$
$h = 15 \text{ cm}$

The area $A$ of a trapezoid is given by the formula:

$$A = \frac{1}{2} h (b_1 + b_2)$$

$$A = 15 \times \frac{1312}{2} \text{ cm}^2$$ $$A = 15 \times 656 \text{ cm}^2$$ $$A = 9840 \text{ cm}^2$$

The area of the trapezoid is $9840 \text{ cm}^2$.