Bala temana ye ka šedi gore o tle o akaretše ka mantšu a gago o šeditše dintlhа tše bohlokwa/dikgopolokgolo mabapi le Kamano ya segwera le mogofe, go ya ka ditaelo tše di latelago:

Step 1: Distance traveled after 7 minutes. Convert time to seconds: t = 7 × 60 = 420~s Distance formula for constant acceleration: s = ut + (1)/(2)at^2 where u=10~m/s, a=1~m/s^2, t=420~s. Substitute values: s = (10)(420) + (1)/(2)(1)(420)^2 (420)^2 = 176400 s = 4200 + (1)/(2)(176400) s = 4200 + 88200 s = 92400~m 92400 m Step 2: Speed after 7 minutes. Speed formula: v = u + at Substitute values: v = 10 + (1)(420) v = 10 + 420 v = 430~m/s 430 m/s Step 3: Time to travel 700 m. Distance formula: s = ut + (1)/(2)at^2 700 = (10)t + (1)/(2)(1)t^2 (1)/(2)t^2 + 10t - 700 = 0 Multiply by 2: t^2 + 20t - 1400 = 0 Quadratic formula: t = -20 ± sqrt(20^2 - 4(1)(-1400)) 2 Discriminant: 400 + 5600 = 6000 sqrt(6000) = sqrt(400 × 15) = 20sqrt(15) Positive root: t = -20 + 20sqrt(15) 2 = -10 + 10sqrt(15)~s -10 + 10sqrt(15) s Step 4: Speed when distance is 700 m. Speed formula: v^2 = u^2 + 2as v^2 = (10)^2 + 2(1)(700) v^2 = 100 + 1400 v^2 = 1500 v = sqrt(1500) = sqrt(100 × 15) = 10sqrt(15)~m/s 10sqrt(15) m/s Step 5: Average speed for 860 m. First, final speed v at s=860~m: v^2 = u^2 + 2as v^2 = 10^2 + 2(1)(860) v^2 = 100 + 1720 v^2 = 1820 v = sqrt(1820) = sqrt(4 × 455) = 2sqrt(455)~m/s Average speed: v_avg = (u + v)/(2) v_avg = 10 + 2sqrt(455)2 v_avg = 5 + sqrt(455)~m/s 5 + sqrt(455) m/s