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Write down the given equations and the values of the tangent functions.

Mathematics

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Answer

x=500 metresx = \text{500 metres}

h=866 metresh = \text{866 metres}

Step-by-step solution

4 steps

Okay, let's solve for xx and hh.

  1. Write down the given equations and the values of the tangent functions.

    We are given two equations:

    1. h=xtan⁡60∘h = x \tan 60^\circ
    2. h=(x+1000)tan⁡30∘h = (x + 1000) \tan 30^\circ We know that tan⁡60∘=3\tan 60^\circ = \sqrt{3} and tan⁡30∘=13\tan 30^\circ = \frac{1}{\sqrt{3}}.
  2. Substitute the tangent values into the equations.

    Substitute tan⁡60∘=3\tan 60^\circ = \sqrt{3} into equation (1):

    h=x3(3)h = x\sqrt{3} \quad (3)

    Substitute tan⁡30∘=13\tan 30^\circ = \frac{1}{\sqrt{3}} into equation (2):

    h=(x+1000)13(4)h = (x + 1000)\frac{1}{\sqrt{3}} \quad (4)
  3. Equate the expressions for hh to solve for xx.

    Set equation (3) equal to equation (4):

    x3=(x+1000)13x\sqrt{3} = (x + 1000)\frac{1}{\sqrt{3}}

    Multiply both sides by 3\sqrt{3} to eliminate the fraction:

    x3⋅3=(x+1000)13⋅3x\sqrt{3} \cdot \sqrt{3} = (x + 1000)\frac{1}{\sqrt{3}} \cdot \sqrt{3} 3x=x+10003x = x + 1000

    Subtract xx from both sides:

    3x−x=10003x - x = 1000 2x=10002x = 1000

    Divide by 2:

    x=10002x = \frac{1000}{2} x=500 metresx = 500 \text{ metres}
  4. Substitute the value of xx into equation (3) to find hh.

    Using h=x3h = x\sqrt{3} and x=500x = 500:

    h=5003h = 500\sqrt{3}

    To get a numerical value, use 3≈1.732\sqrt{3} \approx 1.732:

    h=500×1.732h = 500 \times 1.732 h=866 metresh = 866 \text{ metres}

    The values are:
    x=500 metresx = \boxed{\text{500 metres}}
    h=866 metresh = \boxed{\text{866 metres}}

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