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Draw a circle and label the parts. Briefly explain the parts of the circle. Copy and complete the table below: A straight ladder 10 meters long is placed against a wall with its lower end 6 meters away from the wall. How high up the wall does it reach? Solve for n in the diagram below:
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Step-by-step solution
10 stepsHere are the solutions to the questions.
1. (a) Briefly define communication in your own words
As an AI, I cannot draw. However, I can explain the parts of a circle:
- Center: The point equidistant from all points on the circle.
- Radius: A line segment connecting the center to any point on the circle.
- Diameter: A line segment passing through the center and connecting two points on the circle. Its length is twice the radius.
- Circumference: The total distance around the circle.
- Chord: A line segment connecting any two points on the circle.
1. (b) Copy and complete the table below:
Calculate the Class Boundaries.
For a class interval , the lower class boundary is and the upper class boundary is .
Calculate the Class Width.
Class Width = Upper Class Boundary - Lower Class Boundary.
Calculate the Class Midpoint.
Class Midpoint = .
Complete the table with the calculated values.
Mark Frequency Class Boundaries Class Width Class Midpoint 1-5 5 0.5 - 5.5 5 3 6-10 7 5.5 - 10.5 5 8 11-15 9 10.5 - 15.5 5 13 16-20 3 15.5 - 20.5 5 18 21-25 1 20.5 - 25.5 5 23 26-30 6 25.5 - 30.5 5 28 31-35 4 30.5 - 35.5 5 33 36-40 2 35.5 - 40.5 5 38 2. A straight ladder 10 meters long is placed against a wall with its lower end 6 meters away from the wall. How high up the wall does it reach?
Identify the given values.
This problem forms a right-angled triangle.
Length of the ladder (hypotenuse, ) m.
Distance from the wall (base, ) m.
Height up the wall (height, ) is unknown.Apply the Pythagorean theorem.
The Pythagorean theorem states .
Substitute the values and solve for .
The height the ladder reaches up the wall is 8 meters.
3. Solve for n in the diagram below:
Set up the equation for angles on a straight line.
Angles on a straight line sum to .
Simplify the equation.
Solve for .
The value of is or approximately 17.67.
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