Drow the net and find CSA & Volume

The net of this triangular prism consists of two identical right-angled triangles (the bases) and three rectangular faces.
Imagine unfolding the prism:

• Two triangles, each with sides $0.5 \text{ m}$, $1.2 \text{ m}$, and $1.3 \text{ m}$.
• Three rectangles:
  • One rectangle with dimensions $1.2 \text{ m} \times 2.5 \text{ m}$ (corresponding to the base of the triangle).
  • One rectangle with dimensions $0.5 \text{ m} \times 2.5 \text{ m}$ (corresponding to the height of the triangle).
  • One rectangle with dimensions $1.3 \text{ m} \times 2.5 \text{ m}$ (corresponding to the hypotenuse of the triangle). These three rectangles would be connected side-by-side, forming a larger rectangle with dimensions $(1.2 + 0.5 + 1.3) \text{ m} \times 2.5 \text{ m}$, and the two triangles would be attached to opposite sides of one of the rectangles (e.g., the $1.2 \text{ m} \times 2.5 \text{ m}$ rectangle).