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Evaluate each term with an exponent.

May 17, 2026Mathematics

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Answer

\frac{16}{9}

5 steps

let's simplify this expression.

Evaluate each term with an exponent.
$2^2 = 4$ $3^2 = 9$ $9^{-2} = \frac{1}{9^2} = \frac{1}{81}$ $16^{\frac{1}{2}} = \sqrt{16} = 4$
Substitute the evaluated terms back into the expression.
$4 \times 9 \times \frac{1}{81} \times 4$
Multiply the terms.
$(4 \times 9) \times \frac{1}{81} \times 4$ $36 \times \frac{1}{81} \times 4$ $\frac{36}{81} \times 4$
Simplify the fraction $\frac{36}{81}$ by dividing both numerator and denominator by their greatest common divisor, which is 9.
$\frac{36 \div 9}{81 \div 9} \times 4 = \frac{4}{9} \times 4$
Perform the final multiplication.
$\frac{4}{9} \times 4 = \frac{16}{9}$
The simplified expression is:
$\frac{16}{9}$