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Rewrite the expression using exponent rules.

Mathematics

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Here's the solution for Item 5:

a) Obtain the range of values of xx for which the machine considers the expansion of 1+3x1−3x\sqrt{\frac{1+3x}{1-3x}} as valid.

  1. Rewrite the expression using exponent rules.

    1+3x1−3x=(1+3x)1/2(1−3x)−1/2\sqrt{\frac{1+3x}{1-3x}} = (1+3x)^{1/2} (1-3x)^{-1/2}
  2. Determine the validity range for each binomial expansion.

    For a binomial expansion (1+u)n(1+u)^n to be valid, the condition is ∣u∣<1|u| < 1.
    For (1+3x)1/2(1+3x)^{1/2}, we need ∣3x∣<1|3x| < 1, which

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