Solve the equation: \((3)/(2)(2x−4) = 4(5x−3)\)

$$\frac{3}{2}(2x-4) = 4(5x-3)$$ $$\left(\frac{3}{2} \times 2x\right) - \left(\frac{3}{2} \times 4\right) = (4 \times 5x) - (4 \times 3)$$ $$3x - 6 = 20x - 12$$

Subtract $3x$ from both sides:

$$-6 = 20x - 3x - 12$$ $$-6 = 17x - 12$$

Add 12 to both sides:

$$-6 + 12 = 17x$$ $$6 = 17x$$

Divide both sides by 17:

$$x = \frac{6}{17}$$

The final answer is $\frac{6}{17}$.