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Solve the equation 3p2 - 32 = -5p2 for p.

Mathematics

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Answer

p=±2p = \pm 2

Step-by-step solution

4 steps
  1. Add 5p25p^2 to both sides of the equation to gather all p2p^2 terms on one side.

    3p2−32=−5p23p^2 - 32 = -5p^2 3p2+5p2−32=03p^2 + 5p^2 - 32 = 0 8p2−32=08p^2 - 32 = 0
  2. Add 32 to both sides of the equation to isolate the term with p2p^2.

    8p2=328p^2 = 32
  3. Divide both sides by 8 to solve for p2p^2.

    p2=328p^2 = \frac{32}{8} p2=4p^2 = 4
  4. Take the square root of both sides to solve for pp.

    Remember to include both positive and negative roots.

    p=±4p = \pm\sqrt{4} p=±2p = \pm 2

    The solutions for pp are 2 and −2-2.

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