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In the quadratic equation x2 + px − 10 = 0, if the roots are 2 and -5, what is the value of p?

Mathematics

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Question 50:
The question is partially obscured, but it appears to be asking for the value of pp in the quadratic equation x2+px−10=0x^2 + px - 10 = 0. Given the options, it's highly probable that the question implies specific roots. A common scenario is that the roots are 2 and −5-5, as their product is 2×(−5)=−102 \times (-5) = -10, which matches the constant term.
For a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0, the sum of the roots is −ba-\frac{b}{a} and the product of the roots is ca\frac{c}{a}.
In $x^2 + px

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