Given the equation x² + px − 10 = 0.

Here are the solutions to the questions from the image.

Question 50:
Given the equation $x^2 + px - 10 = 0$.
The question implies that the roots are given in the options, and we need to find $p$. Assuming the roots are 2 and $-5$ (as their product is $-10$, matching the constant term), we can find $p$.

For a quadratic equation $ax^2 + bx + c = 0$, the sum of the roots is $-\frac{b}{a}$.
In this equation, $a=1$, $b=p$, $c=-10$.
Sum of roots $= 2 + (-5) = -3$.
From the formula, sum of roots $=