If 2 + isqrt(3) is a root of the quadratic equation x2 + px + q = 0 where p and q are real numbers, find the values of p and q.

Given that $2 + i\sqrt{3}$ is a root of the equation $x^2 + px + q = 0$, and $p, q \in \mathbb{R}$ (real coefficients), the complex conjugate of this root must also be a root.
So, if $x_1 = 2 + i\sqrt{3}$, then the second root is $x_2 = 2 - i\sqrt{3}$.

For a quadratic equation $x^2 + px + q = 0$, the sum of the roots is given by $x_1 + x_2 = -p$.

For a quadratic equation $x^2 + px + q = 0$, the product of the roots is given by $x_1 \cdot x_2 = q$.

This is in the form $(a+b)(a-b) = a^2 - b^2$.

Since $i^2 = -1$ and $(\sqrt{3})^2 = 3$:

From the calculations, $p = -4$ and $q = 7$.
Therefore, $(p, q) = (-4, 7)$.

Comparing this with the given options, the correct option is (A).

The final answer is $\boxed{\text{(A) } (-4, 7)}$.