Find the equation of a line that passes through (6,6) and which is perpendicular to another line whose equation is 9x - 3y - 6 = 0.

April 13, 2026Mathematics

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April 13, 2026

Answer

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Here are the solutions to the questions:

Question 1: Find the equation of a line that passes through $(6,6)$ and which is perpendicular to another line whose equation is $9x - 3y - 6 = 0$ .

Step 1: Find the gradient of the given line $9x - 3y - 6 = 0$ . Rearrange the equation into the slope-intercept form $y = mx + c$ : $3y = 9x - 6$ $y = \frac{9x}{3} - \frac{6}{3}$ $y = 3x - 2$ The gradient of this line is $m_1 = 3$ .

Step 2

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Question 1: Find the equation of a line that passes through (6,6) and which is perpendicular to another line whose equation is 9x - 3y - 6 = 0.

Asked on April 13, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on April 13, 2026

Here are the solutions to the questions: Question 1: Find the equation of a line that passes through (6,6) and which is perpendicular to another line whose equation is 9x - 3y - 6 = 0. Step 1: Find the gradient of the given line 9x - 3y - 6 = 0. Rearrange the equation into the slope-intercept form y = mx + c: 3y = 9x - 6 y = (9x)/(3) - (6)/(3) y = 3x - 2 The gradient of this line is m_1 = 3. Step 2