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Find the equation of the straight line passing through (0, 8) and (6, 4) in the form y = mx + c.

Mathematics

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The given curve is y=(x−1)2+4y = (x-1)^2 + 4.
The straight line passes through the points (0,8)(0, 8) and (6,4)(6, 4).

a) Find the equation of the straight line in the form y=mx+cy = mx + c.

Step 1: Calculate the gradient (mm) of the straight line.
The line passes through (x1,y1)=(0,8)(x_1, y_1) = (0, 8) and (x2,y2)=(6,4)(x_2, y_2) = (6, 4).

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