This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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Answer
x = 9
You're on a roll — Step 1: Determine the coordinates of the centre O and the point of tangency A. From the diagram 3.4, the centre of the circle is . The point where the tangent touches the circle is .
Step 2: Calculate the gradient of the radius OA. The radius OA connects the centre and the point of tangency . The gradient is given by the formula . Since the gradient of the radius OA is 0, the radius OA is a horizontal line.
Step 3: Determine the equation of the tangent PQ. The tangent line PQ is perpendicular to the radius OA at the point of tangency A. If the radius OA is a horizontal line, then the tangent PQ must be a vertical line. A vertical line passing through a point has the equation . The tangent PQ passes through point . Therefore, the equation of the tangent PQ is .
The equation of the tangent PQ is .
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You're on a roll — Step 1: Determine the coordinates of the centre O and the point of tangency A.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.