Expand the following: (m-2n)5, (3x+y)4, (2y-3x)3

Mathematics
Expand the following: (m-2n)5, (3x+y)4, (2y-3x)3

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Answer

m510m4n+40m3n280m2n3+80mn432n5m^5 - 10m^4n + 40m^3n^2 - 80m^2n^3 + 80mn^4 - 32n^5

Miriam, wacha tuendelee na upanuzi wa binomial.

a) Panua (m2n)5(m-2n)^5

Tunatumia Theorem ya Binomial, ambayo inasema (a+b)N=k=0N(Nk)aNkbk(a+b)^N = \sum_{k=0}^{N} \binom{N}{k} a^{N-k} b^k. Kwa (m2n)5(m-2n)^5, tuna a=ma=m, b=2nb=-2n, na N=5N=5. Viwianishi vya binomial kwa N=5N=5 ni 1,5,10,10,5,11, 5, 10, 10, 5, 1.

Step 1: Andika maneno kwa kutumia viwianishi vya binomial na nguvu za mm na (2n)(-2n). (m2n)5=(50)m5(2n)0+(51)m4(2n)1+(52)m3(2n)2+(53)m2(2n)3+(54)m1(2n)4+(55)m0(2n)5(m-2n)^5 = \binom{5}{0}m^5(-2n)^0 + \binom{5}{1}m^4(-2n)^1 + \binom{5}{2}m^3(-2n)^2 + \binom{5}{3}m^2(-2n)^3 + \binom{5}{4}m^1(-2n)^4 + \binom{5}{5}m^0(-2n)^5

Step 2: Rahisisha kila neno. =1m51+5m4(2n)+10m3(4n2)+10m2(8n3)+5m(16n4)+11(32n5)= 1 \cdot m^5 \cdot 1 + 5 \cdot m^4 \cdot (-2n) + 10 \cdot m^3 \cdot (4n^2) + 10 \cdot m^2 \cdot (-8n^3) + 5 \cdot m \cdot (16n^4) + 1 \cdot 1 \cdot (-32n^5)

Step 3: Fanya kuzidisha. =m510m4n+40m3n280m2n3+80mn432n5= m^5 - 10m^4n + 40m^3n^2 - 80m^2n^3 + 80mn^4 - 32n^5 Upanuzi kamili ni: m510m4n+40m3n280m2n3+80mn432n5\boxed{m^5 - 10m^4n + 40m^3n^2 - 80m^2n^3 + 80mn^4 - 32n^5}

b) Panua (3x+y)4(3x+y)^4

Hapa tuna a=3xa=3x, b=yb=y, na N=4N=4. Viwianishi vya binomial kwa N=4N=4 ni 1,4,6,4,11, 4, 6, 4, 1.

Step 1: Andika maneno kwa kutumia viwianishi vya binomial na nguvu za 3x3x na yy. (3x+y)4=(40)(3x)4y0+(41)(3x)3y1+(42)(3x)2y2+(43)(3x)1y3+(44)(3x)0y4(3x+y)^4 = \binom{4}{0}(3x)^4y^0 + \binom{4}{1}(3x)^3y^1 + \binom{4}{2}(3x)^2y^2 + \binom{4}{3}(3x)^1y^3 + \binom{4}{4}(3x)^0y^4

Step 2: Rahisisha kila neno. =1(81x4)1+4(27x3)y+6(9x2)y2+4(3x)y3+11y4= 1 \cdot (81x^4) \cdot 1 + 4 \cdot (27x^3) \cdot y + 6 \cdot (9x^2) \cdot y^2 + 4 \cdot (3x) \cdot y^3 + 1 \cdot 1 \cdot y^4

Step 3: Fanya kuzidisha. =81x4+108x3y+54x2y2+12xy3+y4= 81x^4 + 108x^3y + 54x^2y^2 + 12xy^3 + y^4 Upanuzi kamili ni: 81x4+108x3y+54x2y2+12xy3+y4\boxed{81x^4 + 108x^3y + 54x^2y^2 + 12xy^3 + y^4}

c) Panua (2y3x)3(2y-3x)^3

Hapa tuna a=2ya=2y, b=3xb=-3x, na N=3N=3. Viwianishi vya binomial kwa N=3N=3 ni 1,3,3,11, 3, 3, 1.

Step 1: Andika maneno kwa kutumia viwianishi vya binomial na nguvu za 2y2y na (3x)(-3x). (2y3x)3=(30)(2y)3(3x)0+(31)(2y)2(3x)1+(32)(2y)1(3x)2+(33)(2y)0(3x)3(2y-3x)^3 = \binom{3}{0}(2y)^3(-3x)^0 + \binom{3}{1}(2y)^2(-3x)^1 + \binom{3}{2}(2y)^1(-3x)^2 + \binom{3}{3}(2y)^0(-3x)^3

Step 2: Rahisisha kila neno. =1(8y3)1+3(4y2)(3x)+3(2y)(9x2)+11(27x3)= 1 \cdot (8y^3) \cdot 1 + 3 \cdot (4y^2) \cdot (-3x) + 3 \cdot (2y) \cdot (9x^2) + 1 \cdot 1 \cdot (-27x^3)

Step 3: Fanya kuzidisha. =8y336xy2+54x2y27x3= 8y^3 - 36xy^2 + 54x^2y - 27x^3 Upanuzi kamili ni: 8y336xy2+54x2y27x3\boxed{8y^3 - 36xy^2 + 54x^2y - 27x^3}

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Quick Answer

Miriam, wacha tuendelee na upanuzi wa binomial. a) Panua (m-2n)^5 Tunatumia Theorem ya Binomial, ambayo inasema (a+b)^N = _k=0^N Nk a^N-k b^k.

Expand the following: (m-2n)5, (3x+y)4, (2y-3x)3
Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI Answer
Miriam, wacha tuendelee na upanuzi wa binomial. a) Panua (m-2n)^5 Tunatumia Theorem ya Binomial, ambayo inasema (a+b)^N = _k=0^N Nk a^N-k b^k. Kwa (m-2n)^5, tuna a=m, b=-2n, na N=5. Viwianishi vya binomial kwa N=5 ni 1, 5, 10, 10, 5, 1. Step 1: Andika maneno kwa kutumia viwianishi vya binomial na nguvu za m na (-2n). (m-2n)^5 = 50m^5(-2n)^0 + 51m^4(-2n)^1 + 52m^3(-2n)^2 + 53m^2(-2n)^3 + 54m^1(-2n)^4 + 55m^0(-2n)^5 Step 2: Rahisisha kila neno. = 1 · m^5 · 1 + 5 · m^4 · (-2n) + 10 · m^3 · (4n^2) + 10 · m^2 · (-8n^3) + 5 · m · (16n^4) + 1 · 1 · (-32n^5) Step 3: Fanya kuzidisha. = m^5 - 10m^4n + 40m^3n^2 - 80m^2n^3 + 80mn^4 - 32n^5 Upanuzi kamili ni: m^5 - 10m^4n + 40m^3n^2 - 80m^2n^3 + 80mn^4 - 32n^5 b) Panua (3x+y)^4 Hapa tuna a=3x, b=y, na N=4. Viwianishi vya binomial kwa N=4 ni 1, 4, 6, 4, 1. Step 1: Andika maneno kwa kutumia viwianishi vya binomial na nguvu za 3x na y. (3x+y)^4 = 40(3x)^4y^0 + 41(3x)^3y^1 + 42(3x)^2y^2 + 43(3x)^1y^3 + 44(3x)^0y^4 Step 2: Rahisisha kila neno. = 1 · (81x^4) · 1 + 4 · (27x^3) · y + 6 · (9x^2) · y^2 + 4 · (3x) · y^3 + 1 · 1 · y^4 Step 3: Fanya kuzidisha. = 81x^4 + 108x^3y + 54x^2y^2 + 12xy^3 + y^4 Upanuzi kamili ni: 81x^4 + 108x^3y + 54x^2y^2 + 12xy^3 + y^4 c) Panua (2y-3x)^3 Hapa tuna a=2y, b=-3x, na N=3. Viwianishi vya binomial kwa N=3 ni 1, 3, 3, 1. Step 1: Andika maneno kwa kutumia viwianishi vya binomial na nguvu za 2y na (-3x). (2y-3x)^3 = 30(2y)^3(-3x)^0 + 31(2y)^2(-3x)^1 + 32(2y)^1(-3x)^2 + 33(2y)^0(-3x)^3 Step 2: Rahisisha kila neno. = 1 · (8y^3) · 1 + 3 · (4y^2) · (-3x) + 3 · (2y) · (9x^2) + 1 · 1 · (-27x^3) Step 3: Fanya kuzidisha. = 8y^3 - 36xy^2 + 54x^2y - 27x^3 Upanuzi kamili ni: 8y^3 - 36xy^2 + 54x^2y - 27x^3 That's 2 down. 3 left today — send the next one.