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Expand the following expressions: (4a - 1)(2a + 3) and (2x + 5)(3x - 4).

Mathematics

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Step-by-step solution

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Here are the solutions to the problems.

  1. Multiply the first terms of (4a−1)(2a+3)(4a - 1)(2a + 3).

    (4a)(2a)=8a2(4a)(2a) = 8a^2
  2. Multiply the outer terms.

    (4a)(3)=12a(4a)(3) = 12a
  3. Multiply the inner terms.

    (−1)(2a)=−2a(-1)(2a) = -2a
  4. Multiply the last terms.

    (−1)(3)=−3(-1)(3) = -3
  5. Combine all terms and simplify.

    8a2+12a−2a−3=8a2+10a−38a^2 + 12a - 2a - 3 = 8a^2 + 10a - 3

    The expanded form is:

    8a2+10a−3\boxed{8a^2 + 10a - 3}
  6. Multiply the first terms of (2x+5)(3x−4)(2x + 5)(3x - 4).

    (2x)(3x)=6x2(2x)(3x) = 6x^2
  7. Multiply the outer terms.

    (2x)(−4)=−8x(2x)(-4) = -8x
  8. Multiply the inner terms.

    (5)(3x)=15x(5)(3x) = 15x
  9. Multiply the last terms.

    (5)(−4)=−20(5)(-4) = -20
  10. Combine all terms and simplify.

    6x2−8x+15x−20=6x2+7x−206x^2 - 8x + 15x - 20 = 6x^2 + 7x - 20

    The expanded form is:

    6x2+7x−20\boxed{6x^2 + 7x - 20}
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