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Expand the expression: 20I(a+3b) + 4(2a-b)

Mathematics

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Answer

20Ia + 60Ib + 8a - 4b\text{20Ia + 60Ib + 8a - 4b}

Step-by-step solution

3 steps

  1. Apply the distributive property to the first term, multiplying $20I$ by each term inside the parenthesis.

    20I(a+3b)=20I⋅a+20I⋅3b=20Ia+60Ib20I(a+3b) = 20I \cdot a + 20I \cdot 3b = 20Ia + 60Ib

  2. Apply the distributive property to the second term, multiplying 4 by each term inside the parenthesis.

    4(2a−b)=4⋅2a+4⋅(−b)=8a−4b4(2a-b) = 4 \cdot 2a + 4 \cdot (-b) = 8a - 4b

  3. Combine the results from Step 1 and Step 2.

    20Ia+60Ib+8a−4b20Ia + 60Ib + 8a - 4b
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