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Expand the terms in the numerator.

Mathematics

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Answer

125−25x−65x2\frac{12}{5} - \frac{2}{5x} - \frac{6}{5x^2}

Step-by-step solution

4 steps
  1. Expand the terms in the numerator.

    The numerator is 5x2(12x2+6x)−(4x3+3x2)⋅105x^2(12x^2+6x) - (4x^3+3x^2) \cdot 10.
    First part:

    5x2(12x2+6x)=(5x2⋅12x2)+(5x2⋅6x)=60x2+2+30x2+1=60x4+30x35x^2(12x^2+6x) = (5x^2 \cdot 12x^2) + (5x^2 \cdot 6x) = 60x^{2+2} + 30x^{2+1} = 60x^4 + 30x^3

    Second part:

    (4x3+3x2)⋅10=(4x3⋅10)+(3x2⋅10)=40x3+30x2(4x^3+3x^2) \cdot 10 = (4x^3 \cdot 10) + (3x^2 \cdot 10) = 40x^3 + 30x^2

    Now substitute these back into the numerator:

    (60x4+30x3)−(40x3+30x2)(60x^4 + 30x^3) - (40x^3 + 30x^2)
  2. Simplify the numerator by combining like terms.

    60x4+30x3−40x3−30x260x^4 + 30x^3 - 40x^3 - 30x^2 60x4+(30x3−40x3)−30x260x^4 + (30x^3 - 40x^3) - 30x^2 60x4−10x3−30x260x^4 - 10x^3 - 30x^2
  3. Expand the denominator.

    The denominator is (5x2)2(5x^2)^2.

    (5x2)2=52⋅(x2)2=25x2⋅2=25x4(5x^2)^2 = 5^2 \cdot (x^2)^2 = 25x^{2 \cdot 2} = 25x^4
  4. Divide the simplified numerator by the simplified denominator.

    The expression becomes:

    60x4−10x3−30x225x4\frac{60x^4 - 10x^3 - 30x^2}{25x^4}

    Divide each term in the numerator by the denominator:

    60x425x4−10x325x4−30x225x4\frac{60x^4}{25x^4} - \frac{10x^3}{25x^4} - \frac{30x^2}{25x^4}

    Simplify each fraction:

    6025−1025x−3025x2\frac{60}{25} - \frac{10}{25x} - \frac{30}{25x^2}

    Reduce the numerical coefficients:

    12⋅55⋅5−2⋅55⋅5x−6⋅55⋅5x2\frac{12 \cdot 5}{5 \cdot 5} - \frac{2 \cdot 5}{5 \cdot 5x} - \frac{6 \cdot 5}{5 \cdot 5x^2} 125−25x−65x2\frac{12}{5} - \frac{2}{5x} - \frac{6}{5x^2}
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