Fresh day NG, let's solve.
Step 1: Rewrite log1012 using prime factorization.
log1012=log10(22×3)
Step 2: Apply the logarithm product rule, log(xy)=logx+logy.
log10(22×3)=log10(22)+log103
Step 3: Apply the logarithm power rule, log(xn)=nlogx.
log10(22)+log103=2log102+log103
Step 4: Substitute the given values, log102=a and log103=b.
2log102+log103=2a+b
The expression for log1012 in terms of a and b is:
2a+b
What's next? Send 'em! 📸