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Express the following to a. 1d.p, b. 2d.p, c. 3d.p. A. 9.23564 B. 12.1464 C. 0.014500081 D. 0.92453 E. 296.0632 2. Find 0.557 x 83.12 to 2d.p 3. A contractor used 0.55...
Mathematics
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2 stepsHere are the solutions to the problems:
1. Express the following to a. 1 d.p. b. 2 d.p. c. 3 d.p.
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A. 9.23564
- 1 d.p.: The second decimal digit is 3, so we round down.
- 2 d.p.: The third decimal digit is 5, so we round up.
- 3 d.p.: The fourth decimal digit is 6, so we round up.
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B. 12.1464
- 1 d.p.: The second decimal digit is 4, so we round down.
- 2 d.p.: The third decimal digit is 6, so we round up.
- 3 d.p.: The fourth decimal digit is 4, so we round down.
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C. 0.014500081
- 1 d.p.: The second decimal digit is 0, so we round down.
- 2 d.p.: The third decimal digit is 1, so we round down.
- 3 d.p.: The fourth decimal digit is 5, so we round up.
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D. 0.92453
- 1 d.p.: The second decimal digit is 2, so we round down.
- 2 d.p.: The third decimal digit is 4, so we round down.
- 3 d.p.: The fourth decimal digit is 5, so we round up.
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E. 296.0632
- 1 d.p.: The second decimal digit is 6, so we round up.
- 2 d.p.: The third decimal digit is 3, so we round down.
- 3 d.p.: The fourth decimal digit is 2, so we round down.
2. Find to 2 d.p.
Multiply the given numbers.
Round the product to 2 decimal places.
The third decimal digit is 7, so we round up the second decimal digit.
The final answer is .
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