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Express the relationship between quantities A, B, and C, given that A varies directly as the square of B and inversely as the square of C.

Mathematics

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Answer

A=kB2C2A = k \frac{B^2}{C^2}

Step-by-step solution

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Here's the solution to question 3:

The problem describes the relationship between three quantities A, B, and C.

  1. Express the direct variation.

    "A varies directly as the square of B" means that AA is proportional to B2B^2.

    A∝B2A \propto B^2
  2. Express the inverse variation.

    "and inversely as the square of C" means that AA is proportional to 1C2\frac{1}{C^2}.

    A∝1C2A \propto \frac{1}{C^2}
  3. Combine the variations into a single proportionality statement.

    A∝B2C2A \propto \frac{B^2}{C^2}
  4. Introduce the constant of proportionality.

    To convert the proportionality into an equation, we introduce a constant kk.

    A=kB2C2A = k \frac{B^2}{C^2}
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