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Write the expression 3a²b + 4ab² as an equivalent algebraic expression.

Mathematics

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Answer

ab(3a + 4b)

Step-by-step solution

8 steps

1.3
To write the expression 3a2b+4ab23a^2b + 4ab^2 as an equivalent algebraic expression, we need to find the greatest common factor (GCF) of the terms and factor it out.

  1. Identify the common factors for the numerical coefficients and variables.

    • The numerical coefficients are 3 and 4. Their GCF is 1.
    • The variable aa appears as a2a^2 and aa. The GCF is aa.
    • The variable bb appears as bb and b2b^2. The GCF is bb.
  2. Multiply the common factors to find the overall GCF.

    The GCF of 3a2b3a^2b and 4ab24ab^2 is 1⋅a⋅b=ab1 \cdot a \cdot b = ab.

  3. Factor out the GCF from each term.

    3a2bab=3a\frac{3a^2b}{ab} = 3a 4ab2ab=4b\frac{4ab^2}{ab} = 4b
  4. Write the expression with the GCF factored out.

    3a2b+4ab2=ab(3a+4b)3a^2b + 4ab^2 = ab(3a + 4b)

    The equivalent algebraic expression is ab(3a+4b)\boxed{ab(3a + 4b)}.

    1.3 Lucy is given the expression below: 7x+357x + 35. Explain to Lucy how to find the equivalent expression.

    To find an equivalent expression for 7x+357x + 35, Lucy needs to factor out the greatest common factor (GCF) from both terms.

  5. Identify the terms in the expression, which are $7x$ and 35.

  6. Find the greatest common factor (GCF) of the numerical coefficients.

    The coefficients are 7 and 35. The largest number that divides both 7 and 35 is 7.

  7. Divide each term in the expression by the GCF.

    • For the first term: 7x÷7=x7x \div 7 = x.
    • For the second term: 35÷7=535 \div 7 = 5.
  8. Write the GCF outside a set of parentheses, and place the results from Step 3 inside the parentheses.

    So, the equivalent expression is 7(x+5)7(x + 5).

    2.1 What do you notice about all 4 terms?

    The given algebraic expression is xy+5y+2x+10xy + 5y + 2x + 10.
    Upon observing all four terms (xyxy, 5y5y, 2x2x, and 10), we notice that they do not share a common factor (other than 1) across all four terms. This indicates that a technique like factoring by grouping might be used.

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