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Factor the expression 45x2 - 20y2.

Mathematics

ScanSolve AI Answer

Answer

5(3x - 2y)(3x + 2y)

Step-by-step solution

5 steps
  1. Identify the expression to be factored.

    The expression is 45x2−20y245x^2 - 20y^2.

  2. Find the greatest common factor (GCF) of the terms.

    The coefficients are 45 and 20. The GCF of 45 and 20 is 5.
    Factor out the GCF from the expression:

    45x2−20y2=5(9x2−4y2)45x^2 - 20y^2 = 5(9x^2 - 4y^2)
  3. Recognize the remaining expression as a difference of squares.

    The expression inside the parentheses, 9x2−4y29x^2 - 4y^2, is in the form A2−B2A^2 - B^2.
    Here, A2=9x2A^2 = 9x^2, so A=9x2=3xA = \sqrt{9x^2} = 3x.
    And B2=4y2B^2 = 4y^2, so B=4y2=2yB = \sqrt{4y^2} = 2y.

  4. Apply the difference of squares formula, A2−B2=(A−B)(A+B)A^2 - B^2 = (A-B)(A+B).

    9x2−4y2=(3x−2y)(3x+2y)9x^2 - 4y^2 = (3x - 2y)(3x + 2y)
  5. Combine the GCF with the factored difference of squares.

    45x2−20y2=5(3x−2y)(3x+2y)45x^2 - 20y^2 = 5(3x - 2y)(3x + 2y)

    The factored expression is:

    5(3x−2y)(3x+2y)5(3x - 2y)(3x + 2y)
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