Factorise by grouping in pairs: ax + ay + 3bx + 3by and 7a + 14b + ax + 2bx

April 21, 2026Mathematics

ScanSolve AI Answer

April 21, 2026

Answer

(a+3b)(x+y)

Here are the factorisations by grouping in pairs:

1. $ax + ay + 3bx + 3by$ Step 1: Group the terms. $(ax + ay) + (3bx + 3by)$ Step 2: Factor out the common factor from each group. $a(x+y) + 3b(x+y)$ Step 3: Factor out the common binomial $(x+y)$ . $\boxed{(a+3b)(x+y)}$

2. $7a + 14b + ax + 2bx$ Step 1: Group the terms. $(7a + 14b) + (ax + 2bx)$ Step 2: Factor out the common factor from each group.

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Quick Answer

1. ax + ay + 3bx + 3by Step 1: Group the terms.

Asked on April 21, 2026Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI AnswerAnswered on April 21, 2026

Here are the factorisations by grouping in pairs: 1. ax + ay + 3bx + 3by Step 1: Group the terms. (ax + ay) + (3bx + 3by) Step 2: Factor out the common factor from each group. a(x+y) + 3b(x+y) Step 3: Factor out the common binomial (x+y). (a+3b)(x+y) 2. 7a + 14b + ax + 2bx Step 1: Group the terms. (7a + 14b) + (ax + 2bx) Step 2: Factor out the common factor from each group. 7(a + 2b) + x(a + 2