We read your photo as:

Factorise completely: 3.1 x2 - x - 12, 3.2 2p2 - 60p - 128, 3.2 (x - 1)2 - 2(x - 1) - 8. Simplify completely: 4.1 (4x2 + 8x) / 2x.

Mathematics

ScanSolve AI Answer

Step-by-step solution

21 steps

here are the factorisations and simplifications:

Factorise completely.

3.1 x2−x−12x^2 - x - 12

  1. Find two numbers that multiply to −12-12 and add to −1-1.

    These numbers are 3 and −4-4.

    x2−x−12=(x+3)(x−4)x^2 - x - 12 = (x + 3)(x - 4)

    The factorised expression is (x+3)(x−4)\boxed{(x + 3)(x - 4)}.

    3.2 2p2−60p−1282p^2 - 60p - 128

  2. Factor out the greatest common factor (GCF), which is 2.

    2p2−60p−128=2(p2−30p−64)2p^2 - 60p - 128 = 2(p^2 - 30p - 64)
  3. Factor the quadratic expression p2−30p−64p^2 - 30p - 64.

    Find two numbers that multiply to −64-64 and add to −30-30. These numbers are 2 and −32-32.

    =2(p+2)(p−32)= 2(p + 2)(p - 32)

    The factorised expression is 2(p+2)(p−32)\boxed{2(p + 2)(p - 32)}.

    3.2 (x−1)2−2(x−1)−8(x - 1)^2 - 2(x - 1) - 8

  4. Let y=(x−1)y = (x - 1).

    Substitute yy into the expression.

    y2−2y−8y^2 - 2y - 8
  5. Factor the quadratic expression.

    Find two numbers that multiply to −8-8 and add to −2-2. These numbers are 2 and −4-4.

    (y+2)(y−4)(y + 2)(y - 4)
  6. Substitute back y=(x−1)y = (x - 1).

    ((x−1)+2)((x−1)−4)((x - 1) + 2)((x - 1) - 4) =(x+1)(x−5)= (x + 1)(x - 5)

    The factorised expression is (x+1)(x−5)\boxed{(x + 1)(x - 5)}.

    QUESTION 4: Simplify completely.

    4.1 4x2+8x2x\frac{4x^2 + 8x}{2x}

  7. Factor the numerator by taking out the common factor $4x$.

    4x(x+2)2x\frac{4x(x + 2)}{2x}
  8. Cancel out the common term $2x$ from the numerator and the denominator.

    =2(x+2)1= \frac{2(x + 2)}{1} =2(x+2)= 2(x + 2)

    The simplified expression is 2(x+2)\boxed{2(x + 2)}.

    4.2 x2−2x−15x2−25\frac{x^2 - 2x - 15}{x^2 - 25}

  9. Factor the numerator x2−2x−15x^2 - 2x - 15.

    Find two numbers that multiply to −15-15 and add to −2-2. These are 3 and −5-5.

    x2−2x−15=(x+3)(x−5)x^2 - 2x - 15 = (x + 3)(x - 5)
  10. Factor the denominator x2−25x^2 - 25.

    This is a difference of squares, a2−b2=(a−b)(a+b)a^2 - b^2 = (a - b)(a + b).

    x2−25=(x−5)(x+5)x^2 - 25 = (x - 5)(x + 5)
  11. Substitute the factored expressions back into the fraction and simplify.

    (x+3)(x−5)(x−5)(x+5)\frac{(x + 3)(x - 5)}{(x - 5)(x + 5)} =x+3x+5= \frac{x + 3}{x + 5}

    The simplified expression is x+3x+5\boxed{\frac{x + 3}{x + 5}}.

    4.3 x(x−1)−(1−x)5x2−5\frac{x(x-1) - (1-x)}{5x^2 - 5}

  12. Simplify the numerator.

    Note that (1−x)=−(x−1)(1 - x) = -(x - 1).

    x(x−1)−(−(x−1))=x(x−1)+(x−1)x(x - 1) - (-(x - 1)) = x(x - 1) + (x - 1)

    Factor out the common term (x−1)(x - 1).

    =(x−1)(x+1)= (x - 1)(x + 1)
  13. Factor the denominator 5x2−55x^2 - 5.

    Factor out the GCF 5, then recognize the difference of squares.

    5x2−5=5(x2−1)=5(x−1)(x+1)5x^2 - 5 = 5(x^2 - 1) = 5(x - 1)(x + 1)
  14. Substitute the factored expressions back into the fraction and simplify.

    (x−1)(x+1)5(x−1)(x+1)\frac{(x - 1)(x + 1)}{5(x - 1)(x + 1)} =15= \frac{1}{5}

    The simplified expression is 15\boxed{\frac{1}{5}}.

    4.4 x2+8x+153x2+9x+x2−256x2+42x\frac{x^2 + 8x + 15}{3x^2 + 9x} + \frac{x^2 - 25}{6x^2 + 42x}

  15. Simplify the first fraction x2+8x+153x2+9x\frac{x^2 + 8x + 15}{3x^2 + 9x}.

    Factor the numerator: x2+8x+15=(x+3)(x+5)x^2 + 8x + 15 = (x + 3)(x + 5).
    Factor the denominator: 3x2+9x=3x(x+3)3x^2 + 9x = 3x(x + 3).
    So, the first fraction becomes: (x+3)(x+5)3x(x+3)=x+53x\frac{(x + 3)(x + 5)}{3x(x + 3)} = \frac{x + 5}{3x}.

  16. Simplify the second fraction x2−256x2+42x\frac{x^2 - 25}{6x^2 + 42x}.

    Factor the numerator: x2−25=(x−5)(x+5)x^2 - 25 = (x - 5)(x + 5).
    Factor the denominator: 6x2+42x=6x(x+7)6x^2 + 42x = 6x(x + 7).
    So, the second fraction becomes: (x−5)(x+5)6x(x+7)\frac{(x - 5)(x + 5)}{6x(x + 7)}.

  17. Add the simplified fractions

    x+53x+(x−5)(x+5)6x(x+7)\frac{x + 5}{3x} + \frac{(x - 5)(x + 5)}{6x(x + 7)}.
    Find the least common denominator (LCD), which is 6x(x+7)6x(x + 7).
    Rewrite the first fraction with the LCD:

    (x+5)3x⋅2(x+7)2(x+7)=2(x+5)(x+7)6x(x+7)\frac{(x + 5)}{3x} \cdot \frac{2(x + 7)}{2(x + 7)} = \frac{2(x + 5)(x + 7)}{6x(x + 7)}
  18. Combine the fractions over the common denominator.

    2(x+5)(x+7)+(x−5)(x+5)6x(x+7)\frac{2(x + 5)(x + 7) + (x - 5)(x + 5)}{6x(x + 7)}
  19. Factor out (x+5)(x + 5) from the numerator.

    (x+5)[2(x+7)+(x−5)]6x(x+7)\frac{(x + 5)[2(x + 7) + (x - 5)]}{6x(x + 7)}
  20. Simplify the expression inside the square brackets.

    2(x+7)+(x−5)=2x+14+x−5=3x+92(x + 7) + (x - 5) = 2x + 14 + x - 5 = 3x + 9

    Factor out 3 from 3x+93x + 9: 3(x+3)3(x + 3).

  21. Substitute this back into the numerator and simplify the entire expression.

    (x+5)⋅3(x+3)6x(x+7)=3(x+3)(x+5)6x(x+7)\frac{(x + 5) \cdot 3(x + 3)}{6x(x + 7)} = \frac{3(x + 3)(x + 5)}{6x(x + 7)} =(x+3)(x+5)2x(x+7)= \frac{(x + 3)(x + 5)}{2x(x + 7)}

    The simplified expression is $\boxed{\frac{(x

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp