Factorise completely (x+4)²-9².

Mathematics

ScanSolve AI Answer

Answer

(x-5)(x+13)

Step-by-step solution

4 steps
  1. Recognize the expression as a difference of squares.

    The expression (x+4)2−92(x+4)^2 - 9^2 is in the form a2−b2a^2 - b^2, where a=(x+4)a = (x+4) and b=9b = 9.

  2. Apply the difference of squares formula, a2−b2=(a−b)(a+b)a^2 - b^2 = (a-b)(a+b).

    Substitute a=(x+4)a=(x+4) and b=9b=9 into the formula:

    (x+4)2−92=((x+4)−9)((x+4)+9)(x+4)^2 - 9^2 = ((x+4) - 9)((x+4) + 9)
  3. Simplify the terms within each parenthesis.

    For the first parenthesis:

    (x+4)−9=x+4−9=x−5(x+4) - 9 = x + 4 - 9 = x - 5

    For the second parenthesis:

    (x+4)+9=x+4+9=x+13(x+4) + 9 = x + 4 + 9 = x + 13
  4. Write the completely factorized expression.

    (x+4)2−92=(x−5)(x+13)(x+4)^2 - 9^2 = (x-5)(x+13) (x−5)(x+13)(x-5)(x+13)
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