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Factorize 2b2 - 10b + 12

Mathematics

ScanSolve AI Answer

Answer

2(b - 2)(b - 3)

Step-by-step solution

4 steps

Here's the step-by-step solution for factoring the quadratic expression:

  1. Identify the coefficients and find two numbers that multiply to a×ca \times c and add to bb.

    For 2b2−10b+122b^2 - 10b + 12, we have a=2a=2, b=−10b=-10, c=12c=12.
    We need two numbers that multiply to 2×12=242 \times 12 = 24 and add up to −10-10. These numbers are −6-6 and −4-4.

  2. Rewrite the middle term using the two numbers found in Step 1.

    2b2−6b−4b+122b^2 - 6b - 4b + 12
  3. Group the terms and factor out the greatest common factor (GCF) from each pair.

    2b(b−3)−4(b−3)2b(b - 3) - 4(b - 3)
  4. Factor out the common binomial factor.

    (2b−4)(b−3)(2b - 4)(b - 3)

    Notice that 2b−42b-4 can be further factored by taking out a GCF of 2.

    2(b−2)(b−3)2(b - 2)(b - 3)
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